In: Statistics and Probability
Given = 252, 12
To find the probability, we need to find the z scores.
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(a) For P( X < 267)
Z = (267 – 252)/12 = 1.25
The required probability from the normal distribution tables is = 0.8944
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(b) For P (234 < X < 255) = P(X < 255) – P(X < 234)
For P( X < 255)
(255 – 252)/12 = 0.25
The probability for P(X < 255) from the normal distribution tables is = 0.5987
For P( X < 234)
(234 – 252)/12 = -1.5
The probability for P(X < 234) from the normal distribution tables is = 0.0668
Therefore the required probability is 0.5987 – 0.0668 = 0.5319
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(c) P(No more than 237) = P(X 237) = P(X < 237)
Z = (237 – 252)/12 = -1.25
The required probability from the normal distribution tables is = 0.1056
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(d) P(X < 222)
Z = (222 – 252)/12 = -2.5
The required probability from the normal distribution tables is = 0.0062
Yes, pretern babies are very unusual as the percentage of such babies is < 5% (0.62%)
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