Question

In: Chemistry

Match each compound in the group on the left with the compound on the right most...

Match each compound in the group on the left with the compound on the right most likely to have the same electrical conductivity per mole in aqueous solution.

Na4[Mo(CN)7H2O]
[Pt(NH3)2Cl2]
Na[RhF6]
[Fe(bipy)3](NO3)2
Li3[Ni(CN)5]
CH3OH
KCl
Cu(NO3)2
CoCl3
Al2(SO4)3

Solutions

Expert Solution

The species in the square bracket will not ionise and the species outside of the square bracket will ionize

Na4[Mo(CN)7H2O] ---> 4Na+ + [Mo(CN)7H2O]4- ----> 5 ions

[Pt(NH3)2Cl2]   ----> no ions ----> 0

Na[RhF6]   ----> Na+ + [RhF6]- -----> 2 ions

[Fe(bipy)3](NO3)2 ----> [Fe(bipy)3]2+ + 2 NO3-    -----> 3 ions

Li3[Ni(CN)5] ---> 3Li+ + [Ni(CN)5]3- -----> 4 ions

--------------------------------------------------------------------------------------

CH3OH ----> do not produce ions

KCl   ---> K+ + Cl- ( 2 ions )

Cu(NO3)2   ---> Cu2+ + 2NO3- ( 3 ions )

CoCl3 ---> Co3+ + 3Cl- ( 4 ions)

Al2(SO4)3 ----> 2Al3+ + 3SO42- ( 5 ions)

So the ions of same are matched each other

queen_honey_blossom answered 2 years ago
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