In: Statistics and Probability
Using the previous tutorial, address the following: Imagine an experiment where three dice are tossed and the numbers on each die is recorded under Die1, Die2 and Die3. Answer the following questions about the sum of the three numbers recorded from: Die1+Die2+Die3. (Discussions allowed)
Hint:
Simulate this experiment 1000 times. (use the same
procedure as in the above tutorial, but for the Number of
Variables, instead of 1 put 3; since we are rolling 3 dice not
one).
Next, create a new column by writing, in cell D1 =A1+B1+C1, and
scroll down the results by clicking on D1 cell and bottom-right
corner. (for more detail see the Book chapter on lecture 26)
Finally create the histogram based on this new column. Use bins
3,4,5,…,18.
16. What is the (approximate) probability that
Die1+Die2+Die3=8?
a. Probability is approximately 5%
b. Probability is approximately 10%
c. Probability is approximately 20%
d. Probability is approximately 25%
17. What is the (approximate) probability that
Die1+Die2+Die3<7?
a. Probability is approximately 5%
b. Probability is approximately 10%
c. Probability is approximately 15%
d. Probability is approximately 20%
18. What is the (approximate) probability that
Max(Die1,Die2,Die3)=5? Careful: Use “Max( ) function in
Excel.
a. Probability is approximately 5%
b. Probability is approximately 15%
c. Probability is approximately 25%
d. Probability is approximately 45%
Computation in Excel:
This image gives the probabilities:
From above image, we get answers as:
16. What is the (approximate) probability that
Die1+Die2+Die3=8?
b. Probability is approximately 10%
17. What is the (approximate) probability that
Die1+Die2+Die3<7?
b. Probability is approximately 10%
18. What is the (approximate) probability that
Max(Die1,Die2,Die3)=5?
c. Probability is approximately 25%
For Histogram:
Edit the X-axis
Once editing of X-axis is done, appropriate changes like deleting the gridlines, making gap between bars as zero can be done by Right click on chart area and bars respectively.
Finally the histogram is obtained.
Table required for histogram
Lower Upper Frequency
0 3 0
3 4 5
4 5 14
5 6 36
6 7 38
7 8 71
8 9 106
9 10 120
10 11 122
11 12 125
12 13 116
13 14 85
14 15 54
15 16 56
16 17 32
17 18 13
18 19 7
19 20 0
Histogram is as follows: