Question

In: Statistics and Probability

The wait time for a computer specialist on the phone is on average 45.7 minutes with...

The wait time for a computer specialist on the phone is on average 45.7 minutes with standard deviation 7.6 minutes. What is the probability that the wait time for help would be 50 minutes or more? Draw and label a picture of a normal distribution with both x and z number lines underneath as in class examples, marked with all relevant values. Show all calculations and state areas to 4 decimal places.

Below what number of minutes would the 4% of shortest wait times occur?

Solutions

Expert Solution

The following is obtained graphically:

Part 2

We know that X is normally distributed, with parameters:

μ=45.7, σ=7.6

We need to find a score x so that the corresponding cumulative normal probability is equal to 0.04. Mathematically, x is such that:

Pr(X≤x)=0.04

The corresponding z score so that the cumulative standard normal probability distribution is 0.04 is

zc​=-1.7507

This value of zc​=-1.7507 can be found either with Excel, or with a normal distribution table. Hence, the X score associated with the 0.04 cumulative probability is

Let me know in the comments if anything is not clear. I will reply ASAP! Please do upvote if satisfied!


Related Solutions

The amount of time (in minutes) that a party hat to wait to be seated in...
The amount of time (in minutes) that a party hat to wait to be seated in a restaurant has an exponential distribution with a mean 15. Find the probability that it will take between 10 and 20 minutes to be seated for a table. If a party has already waited 10 minutes for a table, what is the probability it will be at least another 5 minutes before they are seated? If the restaurant decides to give a free drink...
The wait time (after a scheduled arrival time) in minutes for a train to arrive is...
The wait time (after a scheduled arrival time) in minutes for a train to arrive is Uniformly distributed over the interval [0,12]. You observe the wait time for the next 95 trains to arrive. Assume wait times are independent. Part a) What is the approximate probability (to 2 decimal places) that the sum of the 95 wait times you observed is between 536 and 637? Part b) What is the approximate probability (to 2 decimal places) that the average of...
The amount of time, in minutes that a person must wait for a bus is uniformly...
The amount of time, in minutes that a person must wait for a bus is uniformly distributed between 4 and 16.5 minutes, X~U(4, 16.5). a.) Find the mean of this uniform distribution. b.) Find the standard deviation of this uniform distribution. c.) If there are 16 people waiting for the bus and using the central limit theorem, what is the probability that the average of 16 people waiting for the bus is less than 8 minutes? Please type detailed work...
17#1 a)The wait time (after a scheduled arrival time) in minutes for a train to arrive...
17#1 a)The wait time (after a scheduled arrival time) in minutes for a train to arrive is Uniformly distributed over the interval [0,12]. You observe the wait time for the next 100100 trains to arrive. Assume wait times are independent. Part b) What is the approximate probability (to 2 decimal places) that the average of the 100 wait times exceeds 6 minutes? Part c) Find the probability (to 2 decimal places) that 97 or more of the 100 wait times...
17#4 The wait time (after a scheduled arrival time) in minutes for a train to arrive...
17#4 The wait time (after a scheduled arrival time) in minutes for a train to arrive is Uniformly distributed over the interval [ 0 , 15 ] . You observe the wait time for the next 95 trains to arrive. Assume wait times are independent. Part a) What is the approximate probability (to 2 decimal places) that the sum of the 95 wait times you observed is between 670 and 796? Part b) What is the approximate probability (to 2...
Suppose the mean wait time for a bus is 30 minutes and the standard deviation is...
Suppose the mean wait time for a bus is 30 minutes and the standard deviation is 10 minutes. Take a sample of size n = 100. Find the probability that the sample mean wait time is more than 31 minutes.
Suppose the mean wait time for a bus is 30 minutes and the standard deviation is...
Suppose the mean wait time for a bus is 30 minutes and the standard deviation is 10 minutes. Take a sample of size n = 100. Find the 95th percentile for the sample mean wait time.
Suppose the mean wait time for a bus is 30 minutes and the standard deviation is...
Suppose the mean wait time for a bus is 30 minutes and the standard deviation is 10 minutes. Take a sample of size n = 100. Find the probability that the sample mean wait time is between 29 minutes and 31 minutes.
The following data represent the time, in minutes, that a patient has to wait during 12...
The following data represent the time, in minutes, that a patient has to wait during 12 visits to a doctor’s office before being seen by the doctor: 17 15 20 20 32 28 12 26 25 25 35 24 Use a test at the 0.05 level of significance to test the doctor’s claim that the median waiting time for her patients is not more than 20 minutes. Can you use the Wilcoxon Rank-Sum Test or a t-test? If yes, perform...
The following data represent the time, in minutes, that a patient has to wait during 12...
The following data represent the time, in minutes, that a patient has to wait during 12 visits to a doctor’s office before being seen by the doctor: 17 15 20 20 32 28 12 26 25 25 35 24 Use a test at the 0.05 level of significance to test the doctor’s claim that the median waiting time for her patients is not more than 20 minutes. Perform the Wilcoxon Rank-Sum Test, and then explain why it is an invalid...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT