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Question 24 2 pts (CO7) A restaurant claims the customers receive their food in less than 16 minutes. A random sample of 39 customers finds a mean wait time for food to be 15.8 minutes with a standard deviation of 4.9 minutes. At α = 0.04, what type of test is this and can you support the organizations’ claim using the test statistic? Claim is the alternative, reject the null so support the claim as test statistic (-0.25) is in the rejection region defined by the critical value (-2.05) Claim is the alternative, fail to reject the null so cannot support the claim as test statistic (-0.25) is not in the rejection region defined by the critical value (-1.75) Claim is the null, reject the null so cannot support the claim as test statistic (-0.25) is in the rejection region defined by the critical value (-2.05) Claim is the null, fail to reject the null so support the claim as test statistic (-0.25) is not in the rejection region defined by the critical value (-1.75) Flag this Question

Question 25 2 pts (CO7) A manufacturer claims that their calculators are 6.800 inches long. A random sample of 39 of their calculators finds they have a mean of 6.812 inches with a standard deviation of 0.05 inches. At α=0.08, can you support the manufacturer’s claim using the p value? Claim is the alternative, fail to reject the null and support claim as p-value (0.067) is less than alpha (0.08) Claim is the alternative, reject the null and cannot support claim as p-value (0.134) is greater than alpha (0.08) Claim is the null, reject the null and cannot support claim as p-value (0.067) is less than alpha (0.08) Claim is the null, fail to reject the null and support claim as p-value (0.134) is greater than alpha (0.08)

Answer 1

Q24

Claim is the alternative, fail to reject the null so cannot support the claim as test statistic (-0.25) is not in the rejection region defined by the critical value (-1.75)

Q25

Claim is the null, fail to reject the null and support claim as p-value (0.134) is greater than alpha (0.08)

Explanation:

Q24

= 15.8, =16, n=39, s=4.9

Ho: 16

Ha: < 16

Formula for test statistics is

test statistics = -0.255

Calculate Critical Value for left tailed test with df= n-1 = 39-1=38

We get

Critical value= -1.799

Rule to take decision is

Here (test statistics) > ( critical value)

Hence failed to  reject the null hypothesis(Ho).

Q25

= 6.812, =6.800, n=39, s=0.05

Ho: = 6.800

Ha: 6.800

Formula for test statistics is

test statistics = 1.499

Calculate P-Value for two tailed test with df= n-1 = 39-1=38

We get

P-value = 0.1422

Rule to take decision is

Reject Ho if (p-value) ( )

Here (p-value= 0.1422) > ( =0.08)

Hence Failed to reject the null hypothesis(Ho).