Question

In: Civil Engineering

The dry weight of a natural stone sample is 336 g, the water-saturated weight is 340...

The dry weight of a natural stone sample is 336 g, the water-saturated weight is 340 g, and the water-saturated sample is 196 g in water. The volume of the 50 gr powder sample obtained by grinding the same stone is 18.7 cm3 measured at the picnometer. Calculate the unit weight, specific weight, and weight and volume water absorption rates of this stone.

Solutions

Expert Solution


Related Solutions

“Dry air” is defined as air with no water vapor, and the molecular weight of air,...
“Dry air” is defined as air with no water vapor, and the molecular weight of air, Mair = 28.97 kg/kmol, is for dry air (zero humidity). “Wet air” is typically defined as air with 100% humidity. (a) Calculate the mol fraction of water vapor in wet air at STP conditions. Give your answer in units of PPM to three significant digits. (b) Compare the molecular weight of dry air and wet air at STP conditions. Which air is heavier? Explain....
A sweet, water-saturated natural gas enters a compressor at 50 psia and 100F and leaves at...
A sweet, water-saturated natural gas enters a compressor at 50 psia and 100F and leaves at 200 psia and 300F. a. Is there any chance of water condensing in the compressor? If so, how much? Answer in lb H2O/MMscf gas compressed. b. Estimate the mole fraction of water vapor in the gas stream leaving the compressor. c. The natural gas is then cooled to 190 psia and 100F before entering the second stge of compression. Should a vapor-liquid scrubber be...
Assume a cup contains about 12 oz or 340 g of water at room temperature, about...
Assume a cup contains about 12 oz or 340 g of water at room temperature, about 20 degree C. The electric kettle draws energy from the wall outlet at a rate (Power) of 990W. Draw a single Energy-Interaction Diagram for the process of bringing the water to a rolling boil. Choose an appropriate physical system, as well as an initial and a final point in time and indicate all initial and final conditions on your timeline. Explicitly state any other...
A 25 g piece of metal is dropped into 100.0 g sample of water. The water...
A 25 g piece of metal is dropped into 100.0 g sample of water. The water temperature drops by 5.0 C. The piece of metal's temperature increases by 85 C. What is the specific heat of this piece of metal? (The specific heat of water is 4.18 J/gC)
Compare the water quality of the natural water sample and tap water analyzed. Which quality parameters...
Compare the water quality of the natural water sample and tap water analyzed. Which quality parameters of natural water are significantly different from tap water? What quality parameters you measured in this lab are regulated by the National Primary Drinking Water Standards? Is the quality of the tap water in compliance with these standards? 3. (5107 only, bonus for 4107) Compare the results of sulfate measu
A 50.0-g sample of liquid water at 25.0°C is mixed with 35.0 g of water at...
A 50.0-g sample of liquid water at 25.0°C is mixed with 35.0 g of water at 89.0°C. The final temperature of the water is ________°C.
500 g of saturated liquid water is contained in a piston-cylinder arrangement. The inside diameter of...
500 g of saturated liquid water is contained in a piston-cylinder arrangement. The inside diameter of the cylinder is 100 mm. The water is heated at a constant pressure of 150 kPa until it becomes saturated vapor. Determine (a) the distance through which the piston is raised, and (b) the amount of energy transferred to the water
A 2.85 g lead weight, initially at 11.0 ∘C, is submerged in 7.43 g of water...
A 2.85 g lead weight, initially at 11.0 ∘C, is submerged in 7.43 g of water at 52.2 ∘C in an insulated container. You may want to reference ( pages 349 - 355) section 10.4 while completing this problem. Part A What is the final temperature of both the weight and the water at thermal equilibrium? Express the temperature in Celsius to three significant figures. T = ∘C
A 2.43 g lead weight, initially at 10.6 ∘C, is submerged in 7.78 g of water...
A 2.43 g lead weight, initially at 10.6 ∘C, is submerged in 7.78 g of water at 52.9 ∘C in an insulated container. What is the final temperature of both the weight and the water at thermal equilibrium?
A 48.78−g sample of water at 77.5°C is added to a sample of water at 24.9°C...
A 48.78−g sample of water at 77.5°C is added to a sample of water at 24.9°C in a constant-pressure calorimeter. If the final temperature of the combined water is 38.1°C and the heat capacity of the calorimeter is 26.3 J/°C, calculate the mass of the water originally in the calorimeter.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT