In: Finance
An investor invests $53,030.00 and receives an annuity of $7,000.00 at the end of each year for 12 years and an additional payment of $15,000.00 at the end of the 13th year. Each time he gets a $7,000.00 payment, he immediately deposits $4,000.00 in a savings account that earns 9%. Find the annual yield received by the investor over the 13 year period.
Please provide a mathematical explanation to the answer if possible. I am more concerned with semantics.
The annual yield would be equal to IRR (Internal Rate of Return) of the cash flows.
For IRR calculation, all values with signs intact (-ive for cash outflow) are put in sequencial order & IRR function is used selelcting all the values from 1st to last.
We assume that $4000 savings put in the bank gives a 9% return per annum. The savings are getting added by $4000 every year and interest is getting accumulated to be withdrawn at the end of 13 years.
We would calculate cash flows & then IRR function in excel to calculate the yield
The second column is the cash flow from annuity of $7000 per year.
The third column is the cash flow from annuity of $7000 and the accumulated value of $4000 put in savings account, growing at 9% pa, drawn at the end of 13 years, which equals $87813.54
The yield or return is 15.474%
Year | Cashflow from Annuity | Cashflow from Annuity including Cash Flow from Bank Deposit | ||
0 | (53,030.00) | (53,030.00) | This value is a Cash Outflow & Therefore we use a -ive sign. It is essential | |
1 | 7,000.00 | 7,000.00 | ||
2 | 7,000.00 | 7,000.00 | ||
3 | 7,000.00 | 7,000.00 | ||
4 | 7,000.00 | 7,000.00 | ||
5 | 7,000.00 | 7,000.00 | ||
6 | 7,000.00 | 7,000.00 | ||
7 | 7,000.00 | 7,000.00 | ||
8 | 7,000.00 | 7,000.00 | ||
9 | 7,000.00 | 7,000.00 | ||
10 | 7,000.00 | 7,000.00 | ||
11 | 7,000.00 | 7,000.00 | ||
12 | 7,000.00 | 7,000.00 | ||
13 | 15,000.00 | 102,813.54 | Additional Cash flow from $4000 pa in savings account, which is $87813.54 | |
IRR | 9.658% | 15.474% |
The working of $4000 put in savings bank and earning 9% interest works like below.
The final value in year 13 includes 12 payment periods and 12 interest periods = $87813.54
Year | Opening Balance A | Deposits in Savings A/c (B) |
Interest Earned C = (A+B) x 9% |
Closing Balance (D) = A + B + C | Explanation |
2 | 4,000.00 | - | 360.00 | 4,360.00 | $7000 earned at the end of year 1, $4000 put in the savings account. We start year 2 with an opening balance of $4000, earn interest and close the year2 at $4360 |
3 | 4,360.00 | 4,000.00 | 752.40 | 9,112.40 | $7000 earned at the end of year 2, $4000 put in the savings account. We start year3 with an opening balance of $4360, earn interest and close the year3 at $9112.40 |
4 | 9,112.40 | 4,000.00 | 1,180.12 | 14,292.52 | Same as above |
5 | 14,292.52 | 4,000.00 | 1,646.33 | 19,938.84 | |
6 | 19,938.84 | 4,000.00 | 2,154.50 | 26,093.34 | |
7 | 26,093.34 | 4,000.00 | 2,708.40 | 32,801.74 | |
8 | 32,801.74 | 4,000.00 | 3,312.16 | 40,113.90 | |
9 | 40,113.90 | 4,000.00 | 3,970.25 | 48,084.15 | |
10 | 48,084.15 | 4,000.00 | 4,687.57 | 56,771.72 | |
11 | 56,771.72 | 4,000.00 | 5,469.45 | 66,241.17 | |
12 | 66,241.17 | 4,000.00 | 6,321.71 | 76,562.88 | |
13 | 76,562.88 | 4,000.00 | 7,250.66 | 87,813.54 | This Closing balance is 12 periods of deposits and 12 periods of interest earned |