In: Chemistry
Here a cooling process at constant pressure involves the removal of 3.5 kW from the system.
so( latent heat / sensible heat) q = 3.5 kW = 3009.5 kilocalorie /hour
Now for mass flow rate for (a) air decreasing in temperature from 0oC to -20oC;
Here T1 = 0oC and T2 = 20oC
Now q = mCp (T1-T2)
m = q / [Cp * (T1 -T2) ]
m = 3009.5 (kilocalorie /hour) / [ 0.2403 kcal/(kg oC) * (0+20)oC ]
(here Cp = specific heat of air = 0.2403 kcal/(kg oC)
m = 627 kg/hr = mass flow rate of air required
(b) R12 condensing at -20oC
for condensation
q = m*lemda ( where lemda = latent heat of vapurization of R12 =39.71 Kcal /Kg)
so m = q / lemda
m = 3009.5 (kilocalorie /hour) / 39.71 (Kcal /Kg)
m = 75.79 kg /hr = mass flow rate of R12 required
(c) ammonia condensing at -20oC.
or condensation
q = m*lemda ( where lemda = latent heat of vapurization of NH3 =327.32 Kcal /Kg)
so m = q / lemda
m = 3009.5 (kilocalorie /hour) / 327.32 (Kcal /Kg)
m = 9.20 kg /hr = mass flow rate of NH3 required