Question

Using only loops, no functions and no arrays.

with the heading:

#include <iostream>

using namespace std;

"Write a program that asks the user to enter an integer between 1 and 20. If the user enters an illegal number, the program repeatedly asks the user to enter the correct one. If the user has not entered a correct number after 10 attempts, the program chooses the number 10 as the user's number. The program prints the cube of the user's number.

Answer 1

Below is your code:

#include <iostream>
using namespace std;

int main() {
  //variable to check number of times user entered the input
  int count = 0;
  //variable to hold the number entered by user
  int number;
  //while loop runs maximum of 10 times
  while(count < 10) {
    //increment the counter for each entry
    count++;
    //get input
    cout<<"Enter an integer between 1 and 20: ";
    cin>>number;
    //if number not valid print error message and try again
    if(number < 1 || number > 20) {
      cout<<"Wrong number entered."<<endl;
    } else {
      //if valid number then come out of the loop
      break;
    }
  }
  //if count is 10, then assume 10 as user entry
  if(count == 10) {
    number = 10;
  }
  //printing cube of the entered number
  cout<<"Cube of entered number: "<<(number*number*number)<<endl;

  return 0;
}

Sample Output 1

Sample Output 2