In: Chemistry
3.) Consider this reaction data.
A⟶products
T (K) | k (s–1) |
---|---|
275 | 0.383 |
875 | 0.659 |
If you were going to graphically determine the activation energy of this reaction, what points would you plot? To avoid rounding errors, use at least three significant figures in all values.What is the activation energy of this reaction? Determine the rise, run, and slope of the line formed by these points.
point 1: ?=
point 1: ?=
We need to plot lnK on y axis and 1/T on x axis
K = 0.383
ln K = ln (0.383) = -0.95972
T = 275.0
1/T = 0.00364
point 1 is:
x = 0.00364
y = -0.95972
K = 0.659
ln K = ln (0.659) = -0.41703
T = 875.0
1/T = 0.00114
point 2 is:
x = 0.00114
y = -0.41703
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rise = (y1-y2) = -0.95972 - -0.41703 = -0.54269
rise = (X1-X2) = 0.00364 - 0.00114 = 0.00249
slope = rise/run
= -0.54269/0.00249
= -217.64072
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use
slope = - Ea/R
= -217.64072 = -Ea/8.314
Ea = 1809 J/mol