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A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C...

A voltaic cell employs the following redox reaction:
2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq)
Calculate the cell potential at 25 ∘C under each of the following conditions

a)[Fe3+]= 1.0×10−3 M ; [Mg2+]= 2.00 M

b)[Fe3+]= 2.00 M ; [Mg2+]= 1.0×10−3 M

Solutions

Expert Solution

3Mg(s) -------------> 3Mg^2+ (aq) + 6e^-        E0 = 2.38v

2Fe^3+ (aq) + 6e^- ------> 2Fe(s)                  E0 = -0.04v

--------------------------------------------------------------------------

3Mg(s) + 2Fe^3+ (aq) -----> 3Mg^2+ (aq) + 2Fe(s)   E0cell = 2.34v

    n = 6

Ecell    = E0cell - 0.0592/n logQ

             = 2.34-0.0592/6log[Mg^2+]^3/[Fe^3+]^2

             = 2.34-0.0592/6 log(2)^3/(1*10^-3)^2

            = 2.34-0.00986log8/10^-6

             = 2.34-0.00986*6.9030   = 2.27v

b.

Ecell    = E0cell - 0.0592/n logQ

             = 2.34-0.0592/6log[Mg^2+]^3/[Fe^3+]^2

             = 2.34-0.0592/6 log(1*10^-3)^3/(2)^2

            = 2.34-0.00986*-9.6020   = 2.435v

queen_honey_blossom answered 2 years ago
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