Question

In: Computer Science

use unix Move lines 3 through 5 after line 8 (so the output lines would be...

use unix

Move lines 3 through 5 after line 8 (so the output lines would be in order 1,2,6,7,8,3,4,5,9,10,....)
Given a line with a UNIX path specified, print the base file name only. So for example, "/home/users/james" would print "james"
Given a line with a UNIX path specified, print the directory part only. So for example, "/home/users/james" would print "home/users"

Expert Solution

Move lines 3 through 5 after line 8 (so the output lines would be in order 1,2,6,7,8,3,4,5,9,10,....)

Answer:

I'll be using an awk command in order to execute this.

awk command searches files for text containing a pattern. When a line or text matches, awk performs a specific action on that line/text. The Program statement tells awk what operation to do;

Program statement consists of a series of "rules" where each rule specifies one pattern to search for, and one action to perform when a particular pattern is found.

Code:

awk 'NR==3,NR==5{a[i++]=$0;next} NR==8{print;for(c=0;c<i;c++){print a[c]}next1' file

Awk NR gives you the total number of records being processed or line number

I have a used a for loop in order to acieve the given task done in a single command line argument in Unix

Original Input:

Expected Output:

I could only complete the first part since it had a lot of try and error and I ran out of time. Please Re-Post for receiving answers on the other questions.

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venereology answered 1 year ago

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