Question

In: Statistics and Probability

The American Housing Survey reported the following data on the number of times that owner-occupied and...

The American Housing Survey reported the following data on the number of times that owner-occupied and renter-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months.

Number of Houses (1000s)
Number of Times Owner Occupied Renter Occupied
0 549 23
1 5,012 542
2 6,100 3,734
3 2,544 8,690
4 times or more 558 3,783

Do not round intermediate calculations. Round your answers to two decimal places.

a. Define a random variable x = number of times that owner-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months and develop a probability distribution for the random variable. (Let x = 4 represent 4 or more times.)

x f(x)
0
1
2
3
4
Total

b. Compute the expected value and variance for x.

Total
E(x)
Var(x)

c. Define a random variable y = number of times that renter-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months and develop a probability distribution for the random variable. (Let y = 4 represent 4 or more times.)

y f(y)
0
1
2
3
4
Total

d. Compute the expected value and variance for y.

Total
E(y)
Var(y)

Solutions

Expert Solution

(a) Let, X be a random variable number of times that owner occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months.

A probability distribution for the random variable. (Let x = 4 represent 4 or more times.)

X Number of Houses (1000s) Owner Occupied f(x)
0 549 0.037188
1 5012 0.339497
2 6100 0.413195
3 2544 0.172323
4 558 0.037797
total 14763 1

The f(x) column has been constructed by dividing the number of Houses (1000s) Owner Occupied for each X by the total number of Houses (1000s) Owner Occupied

(b) Expected value of X and variance of X:

Necessary calculation is shown in the table beloiw:

X f(x) x*f(x) x2*f(x)
0 0.037188 0 0
1 0.339497 0.339497 0.339497
2 0.413195 0.82639 1.652781
3 0.172323 0.516968 1.550904
4 0.037797 0.151189 0.604755
total 1 1.834045 4.147937

E(X)=1.834045

Var(X)=4.147937-(1.834045)2

=0.7842159

(c) Let: Y= number of times that renter-occupied units had a water supply stoppage lasting 6 or more hours in the past 3 months .

A probability distribution for the random variable. (Let y = 4 represent 4 or more times.)

Y Renter Occcupied f(y)
0 23 0.001371
1 542 0.032316
2 3734 0.222633
3 8690 0.518125
4 3783 0.225554
Total 16772 1

The f(y) column has been constructed by dividing the number of Houses (1000s) Renter Occupied for each Y by the total number of Houses (1000s) Renter Occupied.

(d) Expected value of Y and variance of Y:

Necessary calculation is shown in the table beloiw:

Y Renter Occcupied f(y) y*f(y) y^2*f(y)
0 23 0.001371 0 0
1 542 0.032316 0.032316
0.58546
0.032316
2 3734 0.222633 0.445266 0.890532
3 8690 0.518125 1.554376 4.663129
4 3783 0.225554 0.902218 3.608872
Total 16772 1 2.934176 9.194849

E(X)=2.934176

Var(X)=9.194849-(2.934176)2

=0.58546

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