The enthrall change for converting 10.0g of ice at -50 C to water at 80 C...

The enthrall change for converting 10.0g of ice at -50 C to water at 80 C is?

Solutions

Expert Solution

q1 = mct

= 10*2.09*(0-(-50)

= 10*2.09*50

= 1045J

q2 = m* heat of fussstion

= 10*333.55 = 3335.5J

q3 = mct

= 10*4.18*(80-0)

= 3344J

q = q1+q2+q3

= 1045+3335.5 + 3344 = 7724.5 J = 7.7245KJ

queen_honey_blossom answered 1 year ago

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