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In: Chemistry

The enthrall change for converting 10.0g of ice at -50 C to water at 80 C...

The enthrall change for converting 10.0g of ice at -50 C to water at 80 C is?

Solutions

Expert Solution

q1    = mct

          = 10*2.09*(0-(-50)

          = 10*2.09*50

           = 1045J

q2      = m* heat of fussstion

           = 10*333.55 = 3335.5J

q3        = mct

             = 10*4.18*(80-0)

              = 3344J

q             = q1+q2+q3

               = 1045+3335.5 + 3344   = 7724.5 J   = 7.7245KJ

queen_honey_blossom answered 3 years ago
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