In: Statistics and Probability
a) What is the probability of a tree being taller than 33 meters? Represent this graphically as well as numerically.
b) A group of 20 trees is selected at random. What is the probability that the average height of these 20 trees is more than 33 meters? Represent this graphically as well as numerically.
c) A group of 20 trees is selected at random. What is the probability that the average height of these trees is between 30 and 32 meters? Represent this graphically as well as numerically.
Solution :
Given that,
mean = = 31
standard deviation = = 4
a ) P (x > 33 )
= 1 - P (x < 33 )
= 1 - P ( x - / ) < ( 33 - 31/ 4)
= 1 - P ( z < 2 / 4 )
= 1 - P ( z < 0.5)
Using z table
= 1 - 0.6915
= 0.3085
Probability = 0.3085
b ) n = 20
= 31
= / n = 4 20 = 0.8944
b ) P ( > 33 )
= 1 - P ( < 33 )
= 1 - P ( - /) < ( 33 - 31/ 0.8944)
= 1 - P ( z < 2 / 0.8944 )
= 1 - P ( z < 2.24)
Using z table
= 1 - 0.9875
= 0.0125
Probability = 0.0125
c ) P (30 < < 32 )
P ( 30 - 31 / 0.8944) < ( - / ) < ( 32 - 31 / 0.8944)
P ( -1/ 0.8944 < z < 1 / 0.8944 )
P (-1.12 < z < 1.12 )
P ( z < 1.12 ) - P ( z < -1.12)
Using z table
= 0.8686 - 0.1314
= 0.7372
Probability = 0.7372