(1) Imagine that we have an electron traveling due west from the capitol of the united...

(1) Imagine that we have an electron traveling due west from the capitol of the united states steps. It is traveling at 98.94% of the speed of light.

(a) What is the force on the electron from the magnetic field?

(b) What is the radius of curvature of the path that it follows?

(c) What would the answers to parts (a)-(c) be for a proton?

Expert Solution

The magnetic field B is defined from the Lorentz Force Law, and specifically from the magnetic force on a moving charge:

The implications of this expression include:

1. The force is perpendicular to both the velocity v of the charge q and the magnetic field B.

2. The magnitude of the force is F = qvB sin? where ? is the angle < 180 degrees between the velocity and the magnetic field. This implies that the magnetic force on a stationary charge or a charge moving parallel to the magnetic field is zero.

3. The direction of the force is given by the right hand rule. The force relationship above is in the form of a vector product.

When the magnetic force relationship is applied to a current-carrying wire, the right-hand rule may be used to determine the direction of force on the wire.

From the force relationship above it can be deduced that the units of magnetic field are Newton seconds /(Coulomb meter) or Newtons per Ampere meter. This unit is named the Tesla. It is a large unit, and the smaller unit Gauss is used for small fields like the Earth's magnetic field. A Tesla is 10,000 Gauss. The Earth's magnetic field at the surface is on the order of half a Gauss.

Magnetic interactions with charge

Magnetic force applications

genius_generous answered 1 year ago

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