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what volume of oxygen gas at 320K and 680torr will react completely with 5.00L of NO...

what volume of oxygen gas at 320K and 680torr will react completely with 5.00L of NO gas at standard temperature and pressure?

Solutions

Expert Solution

     2NO(g) + O2(g) ------------> 2NO2(g)

      2 mole     1 mole

        NO                                                 O2

      V1 = 5L                                          V2 =

     P1   = 760torr                                    P2 = 680 torr

     T1   = 273K                                        T2 = 320K

      n1   = 2                                               n2 = 1

                            P1V1/n1T1    =      P2V2/n2T2

                                    V2           =   P1V1n2T2/n1T1P2

                                                    = 760*5*1*320/2*273*680   = 3.275L

The volume of oxygen 3.275L >>>>answer

Plz any doubt comment in BOX. I will explain .

queen_honey_blossom answered 1 year ago
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