Question
In: Statistics and Probability
Find the critical values, chi Subscript 1 minus alpha divided by 2 Superscript 2 and chi...
Find the critical values, chi Subscript 1 minus alpha divided by 2 Superscript 2 and chi Subscript alpha divided by 2 Superscript 2, for 95% confidence and nequals12. Round to the nearest thousandth.
Solutions
Expert Solution
Solution:
At 95% confidence level the 
is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
/2,df =
0.025,11 = 21.920
and
1-
/2,df =
0.975,11 = 3.816
2L
=
2/2,df
= 21.920
2R
=
21 -
/2,df = 3.816
orchestra answered 3 years agoRelated Solutions
1) Find the critical values chi Subscript Upper R Superscript 2 and chi Subscript Upper L...
1) Find the critical values chi Subscript Upper R Superscript 2
and chi Subscript Upper L Superscript 2 for the given confidence
level c and sample size n. c=0.95, n=19
2) Use technology to construct the confidence intervals for the
population variance sigma squared and the population standard
deviation sigma. Assume the sample is taken from a normally
distributed population. c=0.98 ,s^2=18.49 ,n=30
Find the critical values chi squared Subscript Upper Lχ2L and chi squared Subscript Upper Rχ2R for...
Find the critical values chi squared Subscript Upper Lχ2L and
chi squared Subscript Upper Rχ2R for the given confidence level c
and sample size n. cequals=0.980.98, nequals=2626 chi squared
Subscript Upper Lχ2Lequals=nothing (Round to three decimal places
as needed.)
Find the critical value z Subscript alpha divided by 2 that corresponds to alphaequals0.01. za/2= _____...
Find the critical value z Subscript alpha divided by 2 that
corresponds to alphaequals0.01.
za/2= _____ (Round two decimal places).
Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided...
Do one of the following, as appropriate. (a) Find the critical
value z Subscript alpha divided by 2, (b) find the critical value
t Subscript alpha divided by 2, (c) state that neither the normal
nor the t distribution applies. Confidence level 98%; n=23 SD=
26.2; population appears to be normally distributed.
Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided...
Do one of the following, as appropriate. (a) Find the critical
value z Subscript alpha divided by 2, (b) find the critical value
t Subscript alpha divided by 2, (c) state that neither the normal
nor the t distribution applies. Confidence level 98%; n=23 SD=
26.2; population appears to be normally distributed.
Determine the upper-tail critical value t Subscript alpha divided by 2tα/2 in each of the following...
Determine the upper-tail critical value
t Subscript alpha divided by 2tα/2
in each of the following circumstances.
.a.
1 minus alpha equals 0.90 comma n equals 161−α=0.90, n=16
.d.
1 minus alpha equals 0.90 comma n equals 261−α=0.90, n=26
.b.
1 minus alpha equals 0.95 comma n equals 161−α=0.95, n=16
e.
1 minus alpha equals 0.99 comma n equals 81−α=0.99, n=8
c.
1 minus alpha equals 0.90 comma n equals 681−α=0.90, n=68
Determine the upper-tail critical value t Subscript alpha divided by 2tα/2 in each of the following...
Determine the upper-tail critical value
t Subscript alpha divided by 2tα/2
in each of the following circumstances.
a.a.
1 minus alpha equals 0.90 comma n equals 581−α=0.90, n=58
d.d.
1 minus alpha equals 0.90 comma n equals 131−α=0.90, n=13
b.b.
1 minus alpha equals 0.95 comma n equals 581−α=0.95, n=58
e.e.
1 minus alpha equals 0.99 comma n equals 231−α=0.99, n=23
c.c.
1 minus alpha equals 0.90 comma n equals 301−α=0.90, n=30
a. T= __ (Round to four decimal places...
Determine the upper-tail critical value t Subscript alpha divided by 2tα/2 in each of the following...
Determine the upper-tail critical value
t Subscript alpha divided by 2tα/2
in each of the following circumstances.
a.a.
1 minus alpha equals 0.95 comma n equals 221−α=0.95, n=22
d.d.
1 minus alpha equals 0.95 comma n equals 341−α=0.95, n=34
b.b.
1 minus alpha equals 0.99 comma n equals 221−α=0.99, n=22
e.e.
1 minus alpha equals 0.90 comma n equals 531−α=0.90, n=53
c.c.
1 minus alpha equals 0.95 comma n equals 461−α=0.95, n=46
Click here to view page 1 of the...
Fill in the blank. A critical? value, z Subscript alpha z??, denotes the? _______. A critical?...
Fill in the blank. A critical? value, z Subscript alpha z??,
denotes the? _______. A critical? value, z Subscript alpha z??,
denotes the ?
Deuterium (Subscript 1 Superscript 2 Baseline H) is an attractive fuel for fusion reactions because it...
Deuterium (Subscript 1 Superscript 2 Baseline H) is an
attractive fuel for fusion reactions because it is abundant in the
waters of the oceans. In the oceans, about 0.0177% of the hydrogen
atoms in the water (H2O) are deuterium atoms. (a) How many
deuterium atoms are there in one kilogram of water? (b) If each
deuterium nucleus produces about 7.20 MeV in a fusion reaction, how
many kilograms of ocean water would be needed to supply the energy
needs of...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Using energy level diagrams, predict the relative stability of a Br2 molecule as well as the...
- A 0.0038 kg leaf falls 16.8 m to the ground, where it lands with a speed...
- Problem 1: In the figure to the right, m1=20.0kg and α=53.1o . The coefficient of kinetic...
- A palindrome is a string whose reversal is identical to the string. For example, 110010011 is...
- Explain how the shape of the load duration curve for a particular system affects the selection...
- For physics discussion post. Please TYPE the response as I struggle with reading written information. Explain...
- Consider a file system using a multi-level indexing scheme in inodes as the file organization. In...
ADVERTISEMENT