In: Statistics and Probability
The marks on a statistics midterm test are normally distributed with a mean of 75 and a standard deviation of 6. What is the probability that a sample of 25 exams has a sample mean between 71 and 73?
a. 0.45293
b. 0.04793
c. 0.0475
d. 0.0485
e. 0.04707
Solution :
Given that ,
mean = = 75
standard deviation = = 6
n = 25
= 75
= / n= 6 / 25=1.2
P(71< < 73) = P[(71 - 75) /1.2 < ( - ) / < (73 - 75) /1.2 )]
= P( -3.33< Z < -1.67)
= P(Z <-1.67 ) - P(Z < -3.33)
Using z table
=0.0475 - 0.0004
=0.0471