In: Statistics and Probability
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of business travelers follow.
8 | 8 | 4 | 0 | 5 | 5 | 5 | 4 | 4 | 4 | 4 | 3 | 10 |
6 | 10 | 10 | 0 | 8 | 5 | 4 | 3 | 2 | 4 | 7 | 8 | 9 |
10 | 8 | 4 | 5 | 5 | 4 | 4 | 3 | 8 | 9 | 9 | 5 | 3 |
9 | 8 | 8 | 5 | 10 | 4 | 10 | 5 | 5 | 3 | 3 |
Develop a confidence interval estimate of the population mean rating for Miami. Round your answers to two decimal places.
* *as nothing is mentioned i am using 95 % confidence interval estimate of the population mean rating for Miami,
the necessary calculation table:-
x | x2 |
8 | 64 |
6 | 36 |
10 | 100 |
9 | 81 |
8 | 64 |
10 | 100 |
8 | 64 |
8 | 64 |
4 | 16 |
10 | 100 |
4 | 16 |
8 | 64 |
0 | 0 |
0 | 0 |
5 | 25 |
5 | 25 |
5 | 25 |
8 | 64 |
5 | 25 |
10 | 100 |
5 | 25 |
5 | 25 |
4 | 16 |
4 | 16 |
5 | 25 |
4 | 16 |
4 | 16 |
10 | 100 |
4 | 16 |
3 | 9 |
3 | 9 |
5 | 25 |
4 | 16 |
2 | 4 |
8 | 64 |
5 | 25 |
4 | 16 |
4 | 16 |
9 | 81 |
3 | 9 |
4 | 16 |
7 | 49 |
9 | 81 |
3 | 9 |
3 | 9 |
8 | 64 |
5 | 25 |
10 | 100 |
9 | 81 |
3 | 9 |
sum=287 | sum=2005 |
sample size(n) = 50
degrees of freedom = (n-1)= (50-1) = 49
t critical value for 95% confidence level, df=49,both tailed test be:-
[ from t distribution table]
the 95% confidence interval estimate of the population mean rating for Miami be:-
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