Billie wishes to test the hypothesis that overweight individuals
tend to eat faster than normal weight individuals. To test this
hypothesis, she has two assistance sit in a McDonalds restaurant
and identify individuals who order the Big Mac Special (Big Mac,
fries, and Coke) for lunch. The Big Mackers, as they are
affectionately called by the assistants, are classified as
overweight, normal weight or neither overweight nor normal weight.
The assistants identify 10 overweight and 20 normal weight Big
Mackers. The assistants record the amount of time it takes for the
individuals to complete their Big Mac special meals.
The data is and I need to conduct and analysis
Overweight | Normal Weight |
655 | 876 |
625 | 733 |
557 | 673 |
600 | 700 |
600 | 700 |
700 | 700 |
597 | 852 |
600 | 750 |
501 | 622 |
515 | 756 |
657 | 735 |
650 | 800 |
730 | |
621 | |
688 | |
818 | |
777 | |
783 | |
889 | |
644 |
In: Statistics and Probability
A makeup company wants to know if all the shades of their foundation are sold at equal rates. Below is the gathered data.
Shade #1 | Shade #2 | Shade #3 | Shade #4 | Shade #5 | Shade #6 | Shade #7 |
218 | 191 | 239 | 189 | 178 | 168 | 149 |
Pearson's Chi-square test | ||||||
X-squared = 28.88 | df = 6 | p_value = ? |
Based on the information above, determine if you should accept or reject the null hypothesis that there is no relationship between shade number and number of units sold when alpha = 0.05?
In: Statistics and Probability
Suppose that I flip a coin repeatedly. After a certain number of flips, I tell you that less than 80% of my flips have been “heads”. I flip a few more times, and then tell you that now more than 80% of my (total) flips have been “heads”. Prove that there must have been a point where exactly 80% of my flips had been “heads”. (If we replace 80% with 40%, the statement is not true: if I flip “tails” twice, then “heads” twice, on the fourth flip I jump from 33.3 . . . % to 50% without ever attaining 40%. That is, a correct solution to this problem must use a specific property of 80%.)
In: Statistics and Probability
1. In a survey of U.S. adults with a sample size of 2004, 345 said Franklin Roosevelt was the best president since World War II. TwoTwo U.S. Two adults are selected at random from this sample without replacement. Complete parts (a) through (d).
(a) Find the probability that both adults say Franklin Roosevelt was the best president since World War II.
(b) Find the probability that neither adult says Franklin Roosevelt was the best president since World War II.
(c) Find the probability that at least one of the two adults says Franklin Roosevelt was the best president since World War II.
2. The probability that a person in the United States has type B+ blood is 12%. 4 unrelated people in the United States are selected at random. Complete parts (a) through (d).
(a) Find the probability that all five have type B+ blood.
(b) Find the probability that none of the five have type B+ blood.
(c) Find the probability that at least one of the five has type B+ blood.
3. A study found that 39% of the assisted reproductive technology (ART) cycles resulted in pregnancies. Twenty-five percent of the ART pregnancies resulted in multiple births.
(a) Find the probability that a random selected ART cycle resulted in a pregnancy and produced a multiple birth.
(b) Find the probability that a randomly selected ART cycle that resulted in a pregnancy did not produce a multiple birth.
(c) Would it be unusual for a randomly selected ART cycle to result in a pregnancy and produce a multiple birth? Explain.
In: Statistics and Probability
Hours studied, x |
11 |
10 |
15 |
10 |
6 |
12 |
9 |
10 |
Blood pressure, y |
129 |
130 |
130 |
134 |
129 |
131 |
127 |
128 |
Trying to improve the techniques I use in the classroom and reduce the anxiety of the students, I decided to try an experiment. I decided that I would incorporate more relaxation techniques prior to exams. For a comparison, I subjected the students to twice the exams (evil, I know). In essence, I did a pre- and post-test. The scores are below. At α = 0.05, can it be concluded that the relaxation techniques helped improve test scores?
No relax |
85 |
72 |
91 |
56 |
80 |
94 |
82 |
78 |
68 |
Relax |
87 |
70 |
92 |
68 |
79 |
93 |
86 |
72 |
70 |
In: Statistics and Probability
The editor of the student newspaper was in the process of making some major changes in the newspaper’s layout. He was also contemplat- ing changing the typeface of the print used. To help himself make a decision, he set up an experiment in which 20 individuals were asked to read four newspaper pages, with each page printed in a dif- ferent typeface. If the reading speed differed, then the typeface that was read fastest would be used. However, if there was not enough evidence to allow the editor to conclude that such differences existed, the current typeface would be continued. The times (in seconds) to completely read one page were recorded. What should the editor do?
Typeface 1 | Typeface 2 | Typeface 3 | Typeface 4 |
110 | 123 | 115 | 115 |
118 | 119 | 110 | 134 |
148 | 184 | 139 | 143 |
147 | 145 | 141 | 185 |
159 | 191 | 152 | 171 |
200 | 209 | 194 | 222 |
114 | 116 | 102 | 123 |
148 | 147 | 143 | 151 |
132 | 138 | 127 | 150 |
158 | 175 | 134 | 152 |
159 | 150 | 161 | 177 |
127 | 142 | 131 | 130 |
189 | 202 | 182 | 183 |
167 | 195 | 153 | 174 |
146 | 167 | 136 | 151 |
135 | 126 | 115 | 165 |
124 | 135 | 133 | 122 |
146 | 150 | 143 | 151 |
122 | 136 | 113 | 138 |
129 | 147 | 110 | 137 |
In: Statistics and Probability
A company is developing a new high performance wax for cross country ski racing. In order to justify the price marketing wants, the wax needs to be very fast. Specifically, the mean time to finish their standard test course should be less than
5555
seconds for a former Olympic champion. To test it, the champion will ski the course 8 times. Complete parts a and b below.
a) The champion's times (selected at random) are
59.259.2,
63.563.5,
51.851.8,
53.153.1,
46.746.7,
45.145.1,
52.152.1,
and
40.240.2
seconds to complete the test course. Should they market the wax? Assume the assumptions and conditions for appropriate hypothesis testing are met for the sample. Assume
alphaαequals=0.05.
Choose the correct null and alternative hypotheses below.
In: Statistics and Probability
how do you compute the test error in 5-fold cross-validation?
In: Statistics and Probability
A study has been conducted on the rate of depression and
their relation to demographic features such as age, race,
gender,
etc. The survey was administered to 155 patients and it was
found
women are more likely to be depressed compared to men (Data
extracted from: Gottlieb SS, Khatta M, Friedmann E, et al. The
influence
of age, gender, and race on the prevalence of depression in
heart failure patients. J Am Coll Cardiol. 2004;
43(9):1542-1549.
doi:10.1016/j.jacc.2003.10.064.). The following data related to
the
depression and the gender has been imported from the study:
Depressed Not Depressed Total
Men 54 68 122
Women 21 12 33
Total 75 80 155
a. Set up the null and alternative hypotheses to determine
whether
there is a difference in the depression levels of men and
women.
b. At 0.05 significance level, compute x2 STAT. Is there any
evidence
of a significant difference between the proportion of men
and women and their depression levels?
c. Determine the p-value in (a) and interpret its meaning.
In: Statistics and Probability
More than 100 million people around the world are not getting enough sleep; the average adult needs between 7.5 and 8 hours of sleep per night. College students are particularly at risk of not getting enough shut-eye. A recent survey of several thousand college students indicated that the total hours of sleep time per night, denoted by the random variable X, can be approximated by a normal model with E(X) = 6.84 hours and SD(X) = 1.2 hours.
Question 1. Find the probability that the hours of sleep per night for a random sample of 4 college students has a mean x between 6.6 and 6.91. (use 4 decimal places in your answer)
Question 2. Find the probability that the hours of sleep per night for a random sample of 16 college students has a mean x between 6.6 and 6.91. (use 4 decimal places in your answer)
Question 3. Find the probability that the hours of sleep per night for a random sample of 25 college students has a mean x between 6.6 and 6.91. (use 4 decimal places in your answer)
In: Statistics and Probability
The heights of European 13-year-old boys can be approximated by a normal model with mean μ of 63.1 inches and standard deviation σ of 2.32 inches.
Question 1. What is the probability that a randomly selected 13-year-old boy from Europe is taller than 65.7 inches? (use 4 decimal places in your answer)
Question 2. A random sample of 4 European 13-year-old boys is selected. What is the probability that the sample mean height x is greater than 65.7 inches? (use 4 decimal places in your answer)
Question 3. A random sample of 9 European 13-year-old boys is selected. What is the probability that the sample mean height x is greater than 65.7 inches? (use 4 decimal places in your answer)
Question 4. The Central Limit Theorem was needed to answer questions 1, 2, and 3 above. True False?
In: Statistics and Probability
hello, I'm having trouble understanding how to do these two problems could you show me a step by step.
1)Eight sprinters have made it to the Olympic finals in the 100-meter race. In how many different ways can the gold, silver, and bronze medals be awarded?
2)Suppose that 34% of people own dogs. If you pick two people at
random, what is the probability that they both own a dog?
Give your answer as a decimal (to at least 3 places) or
fraction
In: Statistics and Probability
Data Set for Project 1 | |
Maximum Temperatures by State | |
in the United States | |
for the month of August, 2013 | |
State Name | Max Temps in August 2013 |
AL | 97 |
AK | 97 |
AZ | 45 |
AR | 100 |
CA | 49 |
CO | 109 |
CT | 93 |
DE | 91 |
FL | 102 |
GA | 99 |
HI | 90 |
ID | 97 |
IL | 97 |
IN | 93 |
IA | 100 |
KS | 111 |
KY | 93 |
LA | 97 |
ME | 93 |
MD | 97 |
MA | 97 |
MI | 91 |
MN | 109 |
MS | 97 |
MO | 97 |
MT | 90 |
NE | 108 |
NV | 111 |
NH | 93 |
NJ | 108 |
NM | 106 |
NY | 93 |
NC | 100 |
ND | 88 |
OH | 91 |
OK | 108 |
OR | 97 |
PA | 93 |
RI | 104 |
SC | 97 |
SD | 93 |
TN | 99 |
TX | 104 |
UT | 106 |
VT | 91 |
VA | 102 |
WA | 93 |
WV | 91 |
WI | 90 |
WY | 99 |
If you cannot get the histogram or bar graph features to work, you may draw a histogram by hand and then scan or take a photo (your phone can probably do this) of your drawing and email it to your instructor.
B. Explain how this affects your confidence in the validity of this data set.
Project 1 is due by 11:59 p.m. (ET) on Monday of Module/Week 1.
please help!!!!!!!!
In: Statistics and Probability
A criminologist is interested in possible disparities in the length of prison sentences between males and females convicted in murder-for-hire cases. Selecting 14 cases involving men convicted of trying to solicit someone to kill their wives and 16 cases involving women convicted of women trying to solicit someone to kill their husbands, the criminologist finds the following:
For males, the mean length of the prison sentences is M = 7.34 with SS = 82 For females, the mean length of the prison sentences is M = 9.19 with SS = 214
1. What is the null hypothesis here?
2. What is the alternative hypothesis here?
3. Should a one- or two-tailed test be done here? In answering, say what it is about the description of the research that leads you to your answer.
4. How many df are there for the male sample? How many df are there for the female sample? How many total df are there? And what is the critical value for t, assuming that alpha = .05?
5. What is the variance (s2) for the males? What is the variance (s2) for the females?
6. Compute pooled variance for these groups.
7. Compute the standard error of the difference (s(M1 – M2)).
8. Compute the observed value for t. And what is your decision about H0?
9. If you reject the null hypothesis, compute Cohen's d.
10. Write a conclusion that includes descriptive statistics, group labels, the dependent variable, inferential statistics, and the effect-size measure.
In: Statistics and Probability
A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation.
y | ||||
p(x, y) |
0 | 1 | 2 | |
x | 0 | 0.10 | 0.03 | 0.01 |
1 | 0.07 | 0.20 | 0.07 | |
2 | 0.06 | 0.14 | 0.32 |
(a) Given that X = 1, determine the conditional pmf of Y—i.e., pY|X(0|1), pY|X(1|1), pY|X(2|1). (Round your answers to four decimal places.)
y | 0 | 1 | 2 |
pY|X(y|1) |
(b) Given that two hoses are in use at the self-service island,
what is the conditional pmf of the number of hoses in use on the
full-service island? (Round your answers to four decimal
places.)
y | 0 | 1 | 2 |
pY|X(y|2) |
(c) Use the result of part (b) to calculate the conditional
probability P(Y ≤ 1 | X = 2). (Round
your answer to four decimal places.)
P(Y ≤ 1 | X = 2) =
(d) Given that two hoses are in use at the full-service island,
what is the conditional pmf of the number in use at the
self-service island? (Round your answers to four decimal
places.)
x | 0 | 1 | 2 |
pX|Y(x|2) |
In: Statistics and Probability