Question

In: Statistics and Probability

5 more questions from the first post that I made. Posting questions I don't quite understand...

5 more questions from the first post that I made. Posting questions I don't quite understand or need some help with.

Suppose we want a 93% confidence interval for the average amount spent on books by freshmen in their first year at a major university. The interval is to have a margin of error of $2, and the amount spent has a Normal distribution with a standard deviation σ = $30. The number of observations required is CLOSEST to:
28.
738.
865.
30.
In a statistical test of hypotheses, we say the data are statistically significant at level α if:
the P-value is larger than α.
α is small.
α = 0.05.
the P-value is less than α.
A test statistic in a one-sample t test is described as t(15). From this, we know that the:
sample size used is 15.
sample size used is 16.
mean of the t distribution is 15.
degrees of freedom are 14.
An SRS of 16 items taken from a Normal population yields the average 27.6 and the standard deviation 1.88. To calculate a 95% confidence interval estimate of the population mean, the critical value used in the margin of error is:
z* = 1.96.
t* = 1.746.
z* = 1.645.
t* = 2.131.
The one-sample t statistic from a sample of n = 21 observations for the two-sided test of H0: μ = 60, Ha: μ ≠ 60 has the value t = –1.98. Based on this information:
All of the answers are correct.
we would reject the null hypothesis at α = 0.10.
we would reject the null hypothesis at α = 0.05.
0.025 < P-value < 0.05.

Solutions

Expert Solution

Hence it is closest to 738.

---------------------------

In a statistical test of hypotheses, we say the data are statistically significant at level α if:
the P-value is less than α.

--------------------------

Degree of freedom is df= 15

The sample size is n = 15+1 = 16

A test statistic in a one-sample t test is described as t(15). From this, we know that the:
sample size used is 16.

------------------------------------------

Answer: t* = 2.131

---------------------------------------------------------

Test is two tailed so p-value of the test using excel function "=TDIST(1.98,21-1,2)" is 0.0616.

Since p-value is less than α = 0.10 so we reject the null hypothesis at α = 0.10.

Correct option is

we would reject the null hypothesis at α = 0.10.


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