In: Statistics and Probability
5 more questions from the first post that I made. Posting questions I don't quite understand or need some help with.
Suppose we want a 93% confidence interval for the average amount spent on books by freshmen in their first year at a major university. The interval is to have a margin of error of $2, and the amount spent has a Normal distribution with a standard deviation σ = $30. The number of observations required is CLOSEST to: | |||||||||
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In a statistical test of hypotheses, we say the data are statistically significant at level α if: | |||||||||
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A test statistic in a one-sample t test is described as t(15). From this, we know that the: | |||||||||
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An SRS of 16 items taken from a Normal population yields the average 27.6 and the standard deviation 1.88. To calculate a 95% confidence interval estimate of the population mean, the critical value used in the margin of error is: | |||||||||
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The one-sample t statistic from a sample of n = 21 observations for the two-sided test of H0: μ = 60, Ha: μ ≠ 60 has the value t = –1.98. Based on this information: | |||||||||
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Hence it is closest to 738.
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In a statistical test of hypotheses, we say the data are statistically significant at level α if: | |||
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Degree of freedom is df= 15
The sample size is n = 15+1 = 16
A test statistic in a one-sample t test is described as t(15). From this, we know that the: | |||
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Answer: t* = 2.131
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Test is two tailed so p-value of the test using excel function "=TDIST(1.98,21-1,2)" is 0.0616.
Since p-value is less than α = 0.10 so we reject the null hypothesis at α = 0.10.
Correct option is
we would reject the null hypothesis at α = 0.10.