Questions
The heights of 13-year-old girls are normal distribution with mean 62.6 inches and a standard deviation...

The heights of 13-year-old girls are normal distribution with mean 62.6 inches and a standard deviation of 7.2 inches. Erin is taller than 80% of the girls her age. How tall is Erin?

A researcher wishes to use students' IQ 's to predict their SAT. There is a correlation of 0.82 between SAT scores and IQ scores. The average SAT verbal score is 500, with a standard deviation of 100. The average IQ score is 100 with a standard deviation of 15.

Calculate the equation for the least-squares regression line

In: Statistics and Probability

Before going to the market, a pregnancy test has been applied to a population of 10,000...

Before going to the market, a pregnancy test has been applied to a population of 10,000 women from which 300 were actually pregnant. Suppose this new product  returns a “yes” result 99.5 % of the cases in which the person was actually pregnant and 98% of the cases returns  a “no” result when the person was not pregnant.

Now that the test is in the market: what is the probability that a random user (a women) of the test is not pregnant if the test returns a “yes “ result? Draw  the appropriated probability tree

In: Statistics and Probability

Constructing and Interpreting Confidence Intervals. In Exercises 13–16, use the given sample data and confidence level....

Constructing and Interpreting Confidence Intervals. In Exercises 13–16, use the given sample data and confidence level. In each case, (a) find the best point estimate of the population proportion p; (b) identify the value of the margin of error E; (c) construct the confidence interval; (d) write a statement that correctly interprets the confidence interval.


Medical Malpractice In a study of 1228 randomly selected medical malpractice lawsuits, it was found that 856 of them were dropped or dismissed (based on data from the Physicians Insurers Association of America). Construct a 95% confidence interval for the proportion of medical malpractice lawsuits that are dropped or dismissed.

In: Statistics and Probability

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body...

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a random variable that represents the number of milligrams of porphyrin per deciliter of blood. In healthy circles, x is approximately normally distributed with mean μ = 45 and standard deviation σ = 11. Find the following probabilities. (Round your answers to four decimal places.) (a) x is less than 60 (b) x is greater than 16 (c) x is between 16 and 60 (d) x is more than 60 (This may indicate an infection, anemia, or another type of illness.)

In: Statistics and Probability

Two transmitters send messages through bursts of radio signals to an antenna. During each time slot...

Two transmitters send messages through bursts of radio signals to an antenna. During each time slot each transmitter sends a message with probability 1/2. Simultaneous transmissions result in loss of the messages. Let X be the number of time slots until the first message gets through.

(a) Describe the underlying sample space S of this random experiment and specify the probabilities of its elementary events.

(b) Show the mapping from S to the range of X.

(c) Find the probabilities for the various values of X. Now suppose that terminal 1 transmits with probability 1/2 in a given time slot, but terminal 2 transmits with probability p.

(d) Find the pmf for the number of transmissions X until a message gets through.

(e) Given a successful transmission, find the probability that terminal 2 transmitted.

In: Statistics and Probability

There is some evidence that high school students justify cheating in class on the basis of...

There is some evidence that high school students justify cheating in class on the basis of poor teacher skills.  Poor teachers are thought not to know or care whether students cheat, so cheating in their classes is OK. Good teachers, on the other hand, do care and are alert to cheating, so students tend not to cheat in their classes. A researcher selects three teachers that vary in their teaching performance (Poor, Average, and Good). 6 students are selected from the classes of each of these teachers and are asked to rate the acceptability of cheating in class.

How acceptable is cheating in class?

Extremely unacceptable

Very unacceptable

Somewhat unacceptable

Neutral

Somewhat acceptable

Very acceptable

Extremely acceptable

1

2

3

4

5

6

7

Poor Teacher

Average Teacher

Good Teacher

4

1

2

5

4

1

6

2

2

4

1

3

6

1

3

7

1

1

a. (30 points) Use SPSS to conduct a One-Way ANOVA with α = 0.05 to determine if teacher quality has a significant effect on cheating acceptability. State your hypotheses, report all relevant statistics, include the ANOVA table from SPSS, and state your conclusion.

b. (40 points) Use SPSS to conduct post hoc testing. To run a post hoc test in SPSS, open the One-Way ANOVA window (used above) and click the “Post Hoc” button. Check the boxes next to LSD and Bonferroni.

State the results of the post hoc tests (which means are significantly different from each other) and include SPSS printouts as part of your answer to this question.

In: Statistics and Probability

if I have two lists: A = {132.65, 327.86, 0.08, 1059.22, 5.29, 0.0, 454.04, 0.0, 193.67,...

if I have two lists:

A = {132.65, 327.86, 0.08, 1059.22, 5.29, 0.0, 454.04, 0.0, 193.67, 940.54}

B = {28.31, 0.0, 0.0, 6.71, 2336.61, 0.0, 90.17, 6.4, 244.29, 87.38}

I want to test if the variance of B is greater than A, how should I test it?

what is my Null and Alternative Hypothesis? what test should I run? and what is the result? do I reject my null and why?

In: Statistics and Probability

A 7th grade science teacher was interested in knowing if his after-school tutoring sessions would boost...

A 7th grade science teacher was interested in knowing if his after-school tutoring sessions would boost grades for the students in his classes. The sample consisted of all the children in his 4th and 5th hour classes. The teacher gave a pre-test to each class. Then he held twice weekly sessions for 1 hour after school for four weeks. Students required permission from their parents/guardians in order to attend. Approximately 3/4 of the students for both hours attended. At the end of the 4th week, the teacher gave a post-test and measured the gains/losses in scores. He noted a significant increase in scores and attributed those gains to his tutoring sessions.

1. Identify at least two potential threats to the validity of his study and therefore to the results.

2. Discuss the threats - how might they affect the study results?

3. Propose a method for each threat to reduce/eradicate it.

In: Statistics and Probability

Height: 62, 67, 62, 63, 67, 74, 63, 73, 63 Weight: 130, 140, 102, 140, 145,...

Height: 62, 67, 62, 63, 67, 74, 63, 73, 63

Weight: 130, 140, 102, 140, 145, 157, 130, 190, 135

2. (CLO 1) Construct a confidence interval to estimate the mean height and the mean weight by completing the following:

a. Find the sample mean and the sample standard deviation of the height.

b. Find the sample mean and the sample standard deviation of the weight.

c. Construct and interpret a confidence interval to estimate the mean height.

d. Construct and interpret a confidence interval to estimate the mean weight.

3. (CLO 2) Test a claim that the mean height of people you know is not equal to 64 inches using the p-value method or the traditional method by completing the following:

a. State H0 and H1.

b. Find the p value or critical value(s).

c. Draw a conclusion in context of the situation.

4. (CLO 3) Create a scatterplot with the height on the x-axis and the weight on the y-axis. Find the correlation coefficient between the height and the weight. What does the correlation coefficient tell you about your data? Construct the equation of the regression line and use it to predict the weight of a person who is 68 inches tall.

5. Write a paragraph or two about what you have learned from this process. When you read, see, or hear a statistic in the future, what skills will you apply to know whether you can trust the result?

In: Statistics and Probability

Find the value of z that would be used to test the difference between the proportions,...

Find the value of z that would be used to test the difference between the proportions, given the following. (Use G - H. Give your answer correct to two decimal places.)

Sample n x
G 372 312
H 423 326

In: Statistics and Probability

The following data is the survival time of a set of patients who had Glioblastoma (it...

  1. The following data is the survival time of a set of patients who had Glioblastoma (it is the time from detection until death): {5.28, 6.36, 9.72, 0.25, 5.52, 0.24, 76.8, 15.12, 11.52, 21.84, 2.76, 5.4, 15, 4.8, 1.08}.

Construct a Q-Q plot (normal probability plot) for the data

In: Statistics and Probability

One card is selected from an ordinary deck of 52 cards. Find the conditional probabilities: a)...

One card is selected from an ordinary deck of 52 cards. Find the conditional probabilities:

a) A spade given the card is black_____________

b) A spade given the card is red____________

c) A 4 given the card is not a picture card________________

d) A king given the card is a picture card________________

e) A king given the card is not a 2,3,4, or 5________________

In: Statistics and Probability

Exercise 8.65. A child who gets into an elite preschool will have a lifetime earning potential...

Exercise 8.65. A child who gets into an elite preschool will have a lifetime earning potential given by a Poisson random variable with mean $3,310,000. If the child does not get into the preschool, her earning potential will be Poisson with mean $2,700,000. Let X = 1 if the child gets into the elite preschool, and zero otherwise, and assume that P(X = 1) = p.

(a) Find the covariance of X and the child’s lifetime earnings.

(b) Find the correlation of X and the child’s lifetime earnings.

In: Statistics and Probability

When σ is unknown and the sample is of size n ≥ 30, there are two...

When σ is unknown and the sample is of size n ≥ 30, there are two methods for computing confidence intervals for μ.

Method 1: Use the Student's t distribution with d.f. = n − 1.
This is the method used in the text. It is widely employed in statistical studies. Also, most statistical software packages use this method.

Method 2: When n ≥ 30, use the sample standard deviation s as an estimate for σ, and then use the standard normal distribution.
This method is based on the fact that for large samples, s is a fairly good approximation for σ. Also, for large n, the critical values for the Student's t distribution approach those of the standard normal distribution.

Consider a random sample of size n = 41, with sample mean x = 45.0 and sample standard deviation s = 5.7.

(a) Compute 90%, 95%, and 99% confidence intervals for μ using Method 1 with a Student's t distribution. Round endpoints to two digits after the decimal.

90% 95% 99%
lower limit    
upper limit    

(b) Compute 90%, 95%, and 99% confidence intervals for μ using Method 2 with the standard normal distribution. Use s as an estimate for σ. Round endpoints to two digits after the decimal.

90% 95% 99%
lower limit    
upper limit    

(c) Now consider a sample size of 81. Compute 90%, 95%, and 99% confidence intervals for μ using Method 1 with a Student's t distribution. Round endpoints to two digits after the decimal.

90% 95% 99%
lower limit    
upper limit    

(d) Compute 90%, 95%, and 99% confidence intervals for μ using Method 2 with the standard normal distribution. Use s as an estimate for σ. Round endpoints to two digits after the decimal.

90% 95% 99%
lower limit    
upper limit    

In: Statistics and Probability

You are the manager of a company that owns several outpatient surgery facilities. You want to...

You are the manager of a company that owns several outpatient surgery facilities. You want to determine if there are differences in overall patient health as measured by the General Health Status Score (GHSS) by type of patient carrier (Government, Insured, Uninsured).

Your IT department provided you data on patient visits by type of carrier and the GHSS. Prepare a report to share with the owners of the facility that will help you make informed decisions about whether or not GHSS differ by type of carrier and what the implications of these findings are on operations of the facility. Based on your findings provide recommendations on your plan moving forward to improve the functioning of your facilities in generating revenue. Prepare a report that addresses each of these areas.Purpose(5 points), Importance(5 points), Variables(3 points), Sample Size (2 points), Methodology (5 points), Findings (5 points), Interpretations/Implications (5 points):

Please explain

ID

Insurance Location Wait Time Age GHSS Cost
126 Uninsured Moore 60 11 12 $12,000
107 Uninsured Moore 25 13 99 $7,800
110 Uninsured Moore 45 16 13 $478
141 Uninsured West 34 31 1 $135
160 Insurance Moore 2 47 14 $1,200
128 Uninsured Moore 22 47 16 $4,600
166 Insurance Moore 12 49 77 $4,400
121 Insurance Moore 25 52 15 $4,500
120 Insurance West 15 56 67 $4,450
124 Insurance Moore 22 57 61 $1,200
132 Insurance Moore 54 59 16 $1,200
130 Insurance Moore 55 60 25 $1,200
108 Uninsured Moore 10 60 26 $1,365
161 Insurance Moore 56 62 27 $1,200
115 Government Moore 15 63 66 $13,000
163 Insurance Moore 61 66 34 $1,400
158 Uninsured Moore 56 71 45 $1,300
138 Uninsured Moore 15 74 79 $4,900
113 Government Moore 25 78 56 $13,000
139 Uninsured West 13 78 77 $4,850
180 Government Moore 33 79 86 $12,000
182 Government Moore 34 80 57 $900
176 Government Moore 55 85 79 $1,245
177 Government Moore 60 87 49 $678
178 Government Moore 45 89 73 $450
133 Uninsured West 45 89 93 $9,850
149 Uninsured Moore 14 90 88 $4,500
193 Government Moore 34 90 99 $8,700
114 Government Moore 44 91 90 $5,000
102 Government Pelican 20 5 1 $680
165 Uninsured Pelican 11 5 2 $899
109 Uninsured Pelican 89 6 77 $12,000
152 Insurance Pelican 15 6 77 $14,000
140 Insurance Pelican 20 7 11 $9,000
192 Government West 20 7 13 $450
174 Government Pelican 20 7 15 $6,785
155 Insurance Pelican 20 7 24 $850
112 Government West 22 8 26 $450
169 Insurance Pelican 20 8 36 $960
137 Insurance Pelican 25 9 1 $6,000
194 Government West 22 9 11 $450
156 Insurance West 25 10 13 $11,000
197 Government Pelican 23 12 18 $195
143 Insurance Pelican 26 14 66 $650
164 Uninsured West 22 14 89 $4,500
170 Government West 24 15 99 $4,630
135 Insurance Pelican 31 16 14 $9,000
119 Insurance Pelican 34 17 16 $1,200
196 Government Pelican 24 18 19 $1,645
150 Uninsured Pelican 23 18 25 $879
134 Insurance Pelican 36 19 22 $950
185 Government Pelican 26 19 26 $1,200
145 Government West 28 19 88 $13,000
179 Government West 28 22 1 $456
157 Insurance West 36 22 44 $980
181 Government Pelican 29 24 13 $7,100
144 Insurance Pelican 44 24 36 $1,300
100 Uninsured Pelican 45 27 26 $1,500
159 Insurance Pelican 44 27 48 $15,000
131 Insurance Pelican 45 30 79 $1,500
125 Uninsured Pelican 56 30 99 $12,000
186 Government West 36 34 13 $156
136 Insurance Pelican 45 34 99 $4,500
116 Government West 36 36 16 $4,900
148 Insurance West 48 36 89 $14,800
106 Insurance West 55 38 36 $1,356
129 Insurance Pelican 55 43 46 $4,500
190 Government Pelican 36 44 16 $1,200
123 Insurance Pelican 56 44 36 $1,630
142 Uninsured Pelican 61 45 49 $4,680
117 Government Pelican 39 46 36 $4,950
104 Government Pelican 43 47 12 $4,977
154 Government Pelican 44 48 24 $1,200
103 Government West 46 50 56
$5,500

184 Government Pelican 24 51 57 $5,500
189 Government Pelican 46 55 23 $1,300
122 Government West 49 56 66 $1,230
153 Government West 15 56 99 $5,600
191 Government West 15 57 68 $1,340
183 Uninsured Pelican 9 58 63 $1,345
101 Government Pelican 18 59 89 $8,800
151 Insurance Pelican 14 64 89 $5,600
173 Government Pelican 13 66 23 $2,300
172 Government Pelican 55 67 69 $678
146 Government Pelican 14 67 88 $6,600
175 Government Pelican 24 74 37 $1,300
105 Government Pelican 15 74 88 $8,890
188 Government Pelican 4 76 36 $134
187 Government Pelican 3 78 69 $7,400
162 Insurance Pelican 14 88 90 $2,000
147 Government Pelican 13 88 99 $9,450
168 Government Pelican 13 91 73 $8,700
118 Insurance Pelican 13 91 94 $10,000
167 Insurance Pelican 13 93 93 $8,999
127 Insurance Pelican 14 94 74 $550
171 Government Pelican 14 98 74 $15,000
111 Insurance Pelican 12 99 73 $900
197 Uninsured West 55 80 59 $780
197 Government West 21 19 26 $1,450
197 Uninsured West 14 29 88 $8,900
197 Government West 19 36 44 $1,200
197 Uninsured West 15 36 55 $1,300
197 Government West 17 43 99 $900
197 Uninsured West 16 44 46 $4,400
197 Government West 35 45 78 $7,780
197 Uninsured Pelican 19 45 86 $4,465
197 Uninsured West 60 47 23 $1,200
197 Government Pelican 47 48 22 $1,430
197 Government Pelican 14 55 88 $12,800
197 Insured Pelican 10 65 10 $1,200
197 Government West 46 67 67 $650
197 Insured Pelican 21 69 79 $4,458
197 Insured West 22 70 15 $1,200
197 Insured Pelican 27 73 66 $4,600
197 Insured Pelican 28 74 78 $7,748
197 Insured Pelican 36 76 19 $1,200
197 Insured Pelican 25 77 48 $1,400
197 Government Pelican 13 77 79 $12,000
197 Insured Pelican 44 78 79 $9,900
197 Government Pelican 25 78 99 $1,800
197 Insured Pelican 76 81 89 $4,500
197 Insured Pelican 38 82 79 $5,000
197 Government Pelican 19 89 44 $3,000
197 Government Moore 55 89 96 $5,750
197 Insured Moore 37 89 99 $12,000
197 Government Moore 56 90 79 $10,000
197 Insured Moore 44 94 86 $55
51.18898 53.24409 4486.15

In: Statistics and Probability