Predict the expected number of interruptions for a day that has
150 users per hour on average, using a
point estimate and a 95% interval.
DATA four; INPUT interruptions usage; cards; 0 104.2 2 124.6 5 176.3 6 169.3 1 104.6 2 115.8 3 127.8 6 179.4 8 210.5 4 126.7 0 100.5 1 119.5 1 123.8 0 106.4 4 156.7 3 148.2 5 156.2 6 167.3 8 198.2 2 124.6 3 145.9 4 156.2 ; run;
In: Statistics and Probability
Show X(1) (first oder statistics) is complete by definition.
In: Statistics and Probability
Reformulate your hypothesis test from your week 5 discussion to incorporate a 2-sample hypothesis test, as specified in Chapter 10. What would be your data? What is your null hypothesis? What is your alternate hypothesis? What would be your Type 1 and Type 2 errors relative to your decision? Suppose you have a p-value of 0.01, what does this mean relative to your problem and decision? Suppose your p-value is 0.20, what does this mean relative to your problem and decision? If you reformulated your design for 3 or more samples, what would be the implications of interaction? When would you use the Tukey HSD or the Tukey-Kramer test, and WHY?
In: Statistics and Probability
1.
a.) Let z be a random variable with a standard normal distribution. Find the indicated probability. (Enter your answer to four decimal places.) P(−2.20 ≤ z ≤ 1.01) =
b.) Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(−1.76 ≤ z ≤ −1.17) =
c.) Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) μ = 15.1; σ = 4.1
P(10 ≤ x ≤ 26) =
d.) Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) μ = 14.6; σ = 3.6
P(8 ≤ x ≤ 12) =
e.) Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) μ = 100; σ = 15
P(x ≥ 120) =
f.) Find z such that 3.0% of the standard normal curve lies to the left of z. (Round your answer to two decimal places.) z =
g.) Find z such that 57% of the standard normal curve lies to the right of z. (Round your answer to two decimal places.) z =
h.) A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose per deciliter (1/10 of a liter) of blood. Suppose that after a 12-hour fast, the random variable x will have a distribution that is approximately normal with mean μ = 86 and standard deviation σ = 21. Note: After 50 years of age, both the mean and standard deviation tend to increase. For an adult (under 50) after a 12-hour fast, find the following probabilities. (Round your answers to four decimal places.)
(i) x is more than 60
(ii) x is less than 110
(iii) x is between 60 and 110
(iv) x is greater than 125 (borderline diabetes starts at
125)
i.) Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 4.6 millimeters (mm) and a standard deviation of 1.5 mm. For a randomly found shard, find the following probabilities. (Round your answers to four decimal places.)
(i) the thickness is less than 3.0 mm
(ii) the thickness is more than 7.0 mm
(iii) the thickness is between 3.0 mm and 7.0 mm
In: Statistics and Probability
Consider the AR(1) model xt = 0:5x_t-1 + w_t. Derive the partial acf hh when h = 1 and 2. Show your work or provide justification. You need to start from the definition.
In: Statistics and Probability
What is the probability that Z is less than minus − 0.27 0.27 or greater than the mean? The probability that Z is less than minus − 0.27 0.27 or greater than the mean is 0.8936
In: Statistics and Probability
F | G |
0 | 76.15 |
1 | 75.63 |
2 | 74.67 |
3 | 73.69 |
4 | 72.71 |
5 | 71.72 |
6 | 70.73 |
7 | 69.74 |
8 | 68.75 |
9 | 67.76 |
10 | 66.76 |
11 | 65.77 |
12 | 64.78 |
13 | 63.79 |
14 | 62.8 |
15 | 61.82 |
16 | 60.84 |
17 | 59.88 |
18 | 58.91 |
19 | 57.96 |
20 | 57.01 |
21 | 56.08 |
22 | 55.14 |
23 | 54.22 |
24 | 53.29 |
25 | 52.37 |
26 | 51.44 |
27 | 50.52 |
28 | 49.59 |
29 | 48.67 |
30 | 47.75 |
31 | 46.82 |
32 | 45.9 |
33 | 44.98 |
34 | 44.06 |
35 | 43.14 |
36 | 42.22 |
37 | 41.3 |
38 | 40.38 |
39 | 39.46 |
40 | 38.54 |
41 | 37.63 |
42 | 36.72 |
43 | 35.81 |
44 | 34.9 |
45 | 34 |
46 | 33.11 |
47 | 32.22 |
48 | 31.34 |
49 | 30.46 |
50 | 29.6 |
51 | 28.75 |
52 | 27.9 |
53 | 27.07 |
54 | 26.25 |
55 | 25.43 |
56 | 24.63 |
57 | 23.83 |
58 | 23.05 |
59 | 22.27 |
60 | 21.51 |
61 | 20.75 |
62 | 20 |
63 | 19.27 |
64 | 18.53 |
65 | 17.81 |
66 | 17.09 |
67 | 16.38 |
68 | 15.68 |
69 | 14.98 |
70 | 14.3 |
71 | 13.63 |
72 | 12.97 |
73 | 12.33 |
74 | 11.7 |
75 | 11.08 |
76 | 10.48 |
77 | 9.89 |
78 | 9.33 |
79 | 8.77 |
80 | 8.24 |
81 | 7.72 |
82 | 7.23 |
83 | 6.75 |
84 | 6.3 |
85 | 5.87 |
86 | 5.45 |
87 | 5.06 |
88 | 4.69 |
89 | 4.35 |
90 | 4.03 |
91 | 3.73 |
92 | 3.46 |
93 | 3.21 |
94 | 2.99 |
95 | 2.8 |
96 | 2.63 |
97 | 2.48 |
98 | 2.34 |
99 | 2.22 |
100 | 2.11 |
Flavor |
Cherry |
Strawberry |
Chocolate |
Orange |
Lime |
Expected % |
30% |
20% |
20% |
15% |
15% |
A bag bought at random has the following number of mints in it.
Flavor |
Cherry |
Strawberry |
Chocolate |
Orange |
Lime |
Observed |
67 |
50 |
54 |
29 |
25 |
Determine whether this distribution is consistent with company’s stated proportions.
3. This problem is the check to see whether you understand the X-squared test. There are only 2 test columns, so you cannot use the X-squared Goodness of Fit applet from the previous problem as it requires 3 or more test intervals.
You are told that a genetics theory says the ratio of tall:short plants is 3:1. You test this claim by growing 200 plants. You obtain 160 tall plants and 40 short plants. Using a X-squared test, determine whether or not your results supports the tall:short = 3:1 claim.
Card Color |
Observed |
Expected |
(O – E) |
(O-E)2 |
(O-E)2/E |
Red |
160 |
||||
Black |
40 |
||||
Sum |
200 |
200 |
0 |
n/a |
In: Statistics and Probability
Exercise Group |
Sample Size |
Sample Mean |
Sample Standard Deviation |
Low |
37 |
78.40541 |
11.422345 |
Moderate |
59 |
74.18644 |
9.861934 |
High |
14 |
67.78571 |
10.990755 |
MSE = 111.3 F = 5.355 p-value = 0.00607
Bonferroni Modified Alpha = 0.5/3 = 0.0167
Run the Bonferroni procedure to compare each pair of group means. Compute each pair’s difference in means, standard error (using the MSE found above), p-value, and conclusion of significance or non-significance.
In: Statistics and Probability
A | C | D | |
11 | 211 | 211 | |
12 | 125 | 121 | |
7 | 179 | 185 | |
12 | 225 | 222 | |
11 | 161 | 157 | |
15 | 170 | 174 | |
6 | 191 | 184 | |
16 | 195 | 194 | |
12 | 135 | 133 | |
13 | 162 | 165 | |
9 | |||
14 | |||
11 | |||
10 | |||
8 | |||
15 | |||
14 | |||
13 | |||
9 | |||
6 | |||
8 | |||
12 | |||
14 | |||
16 | |||
11 |
Use the central limit theorem to the following questions.
We want to test to see whether the data taken from 25 test experiments is consistent with the mean equal to 10.3 (µ = 10.3), or is more consistent with the mean greater than 10.3 (µ > 10.3).
Use Summary 5b, Table 2, Column 1.
You are measuring weight loss using the same set of people at different times C and D. You want to know whether there is any difference in the weight between the start of the diet and the end of the diet. Column C gives the weight at the beginning of diet time. Column D gives the weight for the SAME person at the end of the diet time. Since there is data for the same person at different times, we will test whether µ(C-D) <= 0 or µ(C-D) > 0 (meaning the diet did cause weight loss) since we have correlated data (matched pairs).
Use Summary 5b, Table 2, Column 1
In: Statistics and Probability
In: Statistics and Probability
Can we conclude that the mean time for a game is less than 3.5 hours? Use the .05 significance level.
In: Statistics and Probability
The response times for a random sample of 40 medical emergencies provided a mean of 13.25 minutes. The population standard deviation (σ) is believed to be 3.2 minutes.
The EMS director wants to perform a hypothesis test and if the data provide enough evidence that the response time is longer than 12 minutes, the director will conclude that the emergency service is not meeting the response goal.
Test the above hypothesis using the .05 level of significance. (Hint: because you know σ, you will use the Z table to find the critical value(s)).
In: Statistics and Probability
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 411.0 gram setting. It is believed that the machine is underfilling the bags. A 41 bag sample had a mean of 404.0 grams. A level of significance of 0.01 will be used. Determine the decision rule. Assume the variance is known to be 784.00.
In: Statistics and Probability
1. Suppose we wish to find the required sample size to find a 90% confidence interval for the population proportion with the desired margin of error. If there is no rough estimate of the population proportion, what value should be assumed for ?
0.90 |
||
0.10 |
||
0.50 |
||
0.05 |
2. An analyst takes a random sample of 25 firms in the
telecommunications industry and constructs a confidence interval
for the mean return for the prior year. Holding all else constant,
if he increased the sample size to 30 firms, how are the standard
error of the mean and the width of the confidence interval
affected?
Standard error of the mean | Width of confidence interval | |
A | Increases | Becomes wider |
B | Increases | Becomes narrower |
C | Decreases | Becomes wider |
D | Decreases | Becomes narrower |
1.96(10.24/6) |
||
1.96(3.20/6) |
||
1.645(3.20/6) |
||
1.645(10.24/6) |
3. For a given confidence level and population standard deviation, which of the following is true in the interval estimation of the population mean?
If the sample size is bigger, the interval is narrower. |
||
If the population size is smaller, the interval is narrower. |
||
If the population size is bigger, the interval is narrower. |
||
If the sample size is smaller, the interval is narrower. |
In: Statistics and Probability
An urn contains 5 white and 8 red balls. Assume that white balls are numbered. Suppose that 3 balls are chosen with replacement from that urn. Let Yi = 1 if if the ith white ball is selected and Yi = 0 otherwise, i = 1,2:
Find the EXPECTED VALUE of Yi given that a) Y2 = 1; b) Y2 = 0.
In: Statistics and Probability