In: Statistics and Probability
a. all Hypothesis Tests must include all four steps, clearly labeled;
b. all Confidence Intervals must include all output as well as the CI itself
c. include which calculator function you used for each problem.
3. At a community college, the mathematics department has been experimenting with four different delivery mechanisms for content in their Statistics courses. One method is traditional lecture (Method I), the second is a hybrid format in which half the time is spent online and half is spent in-class (Method II), the third is online (Method III), and the fourth is an emporium model from which students obtain their lectures and do their work in a lab with an instructor available for assistance (Method IV). To assess the effective of the four methods, students in each approach are given a final exam with the results shown in the following table. Assume an approximate normal distribution for each method. At the 5% significance level, does the data suggest that any method has a different mean score from the others?
Method I | 81 | 81 | 85 | 67 | 88 | 72 | 80 | 63 | 62 | 92 | 82 | 49 | 69 | 66 | 74 | 80 |
Method II | 85 | 53 | 80 | 75 | 64 | 39 | 60 | 61 | 83 | 66 | 75 | 66 | 90 | 93 | ||
Method III | 81 | 59 | 70 | 70 | 64 | 78 | 75 | 80 | 52 | 45 | 87 | 85 | 79 | |||
Method IV | 86 | 90 | 81 | 61 | 84 | 72 | 56 | 68 | 82 | 98 | 79 | 74 | 82 |
In: Statistics and Probability
A psychic claims to be able to predict the outcome of coin flips before they happen. Someone who guesses randomly will predict about half of coin flips correctly. In 100 flips, the psychic correctly predicts 57 flips. Do the results of this test indicate that the psychic does better than random guessing? The hypotheses are Ho:p=0.50 Ha:p>50 where p is the proportion of correct coin flip predictions by the psychic.
1. Give the test statistic for this problem.
Group of answer choices
a.Z = 1.40
b.Z = -9.43
c.Z = -1.40
2. What is the P value
a P-value = 0.2843
b P-value = 0.919
c P-value = 0.081
d P-value = 0.162
3. Give the conclusion based on the P-value above. Use a 5% level of significance.
a. Someone who guesses randomly will predict about half of coin flips correctly (about 50 out of 100). In 100 flips, the psychic correctly predicts 57 flips, a 14% increase. Therefore we can conclude that the psychic's predictions are not due to random chance.
b The psychic correctly predicted 57% of the coin flips (57 out of 100). A person who guesses randomly will correctly predict about 50% (half) of the 100 coin flips. So the psychic's predictions are significantly better.
c The psychic’s prediction of the outcomes of coin flips is not significantly better than we would expect with random guessing.
In: Statistics and Probability
PLEASE DO NOT COPY OTHERS ANSWER, THANK YOU!
Let x1, x2, · · · , xn ∈ {0, 1}.
(a) (10 points) Consider the equation x1 + x2 + · · · + xn = 0 mod 2. How many solutions does this equation have? Express your answer in terms of n. For example, if n = 2, x1 + x2 = 0 has 2 solutions: (x1, x2) = (0, 0) and (x1, x2) = (1, 1).
(b) (5 points) Consider the equations x1 + x2 + · · · + xn = 0 mod 2 x1 + x2 + · · · + x10 = 0 mod 2 for n ≥ 10. How many solutions are there satisfying both equations?
In: Statistics and Probability
A researcher is interested in determining whether there is a correlation between number of packs of cigarettes smoked per day and longevity (in years). n=10.
Longevity
# packs of cigarettes smoked (X) |
(Y) |
0 |
80 |
0 |
70 |
1 |
72 |
1 |
70 |
2 |
68 |
2 |
65 |
3 |
69 |
3 |
60 |
4 |
58 |
4 |
55 |
In: Statistics and Probability
PLEASE DO NOT COPY OTHERS ANSWER, THANK YOU!
Alice and Bob play the following game: in each round, Alice first rolls a single standard fair die. Bob then rolls a single standard fair die. If the difference between Bob’s roll and Alice's roll is at most one, Bob wins the round. Otherwise, Alice wins the round.
(a) (5 points) What is the probability that Bob wins a single round?
(b) (7 points) Alice and Bob play until one of them wins three rounds. The first player to three wins is declared the winner of the series. What is the probability that Bob wins the series?
(c) (7 points) In a single series, what is the expected number of wins for Bob?
(d) (6 points) In a single series, how many more games is Alice expected to win than Bob? That is, what is the expected value of the number of wins for Alice minus the number of wins for Bob?
(e) (5 points) In a single series, what is the variance of the expected number of wins for Bob?
In: Statistics and Probability
A thermal interaction between two components requires that both components have similar temperature. One random sample for each component was obtained. The data is summarized in the table below:
Component 1 |
55 |
54 |
53 |
54 |
Component 2 |
54 |
52 |
53 |
In: Statistics and Probability
To help answer the question, here is the "previous problem":
In: Statistics and Probability
(A-Grade) The operations manager of a large production plant would like to estimate the mean amount of time a worker takes to assemble a new electronic component. Assume that the population standard deviation of time for this assembly is 3.6 minutes.
1. After observing 120 workers assembling similar devices, the manager noticed that their average time was 16.2 minutes. Construct a 92% confidence interval for the mean assembly time.
2. How many workers should be involved in this study in order to have the mean assembly time estimated up to 15 seconds with 92% confidence?
3. In a second study a sample 102 workers had standard deviation of 2.78 minutes, with 95% confidence level, construct a confidence interval for the population standard deviation.
In: Statistics and Probability
The company has a new process for manufacturing large artificial sapphires. In a trial run, 12 sapphires are produced. The mean weight for these 12 gems is x = 6.75 carats, and the sample standard deviation s = 0.33 carats. Find the 95% confidence interval for the population mean weight of artificial sapphires.
In: Statistics and Probability
True/False
Type T (for True) or F (for False) for each statement for both Discrete and Continuous random variables.
In: Statistics and Probability
Identify the Distribution
Select the Distribution that best fits the definition of the random variable X in each case.
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In: Statistics and Probability
Assuming all of the distributions are normal, find the x for each of the cases:
a. P(Z < k) = 0.92
b. P(Z > k) = 0.72
c. P(−1 < Z < k) = 0.60
d. (A-Grade) P(k < Z < 1.7) = 0.57
e. (A-Grade) P(Z = k) = 0.00
In: Statistics and Probability
Fast Facts Financial (FFF), Inc. provides credit reports to lending institutions which are
evaluating applicants for home mortgages, vehicle, home equity, and other loans.
A pressure faced by FFF Inc. is that several competing credit reporting companies are
able to provide reports in about the same average amount of time, but are able to promise
a lower time than FFF Inc - the reason being that the variation in time required to
compile and summarize credit data is smaller than the time required by FFF.
FFF has identified & implemented procedures which they believe will reduce this
variation. If the historic standard deviation is 2.3 days, and the standard deviation for a
sample of 25 credit reports under the new procedures is 1.8 days, then test the appropriate
hypothesis at the alpha = .05 level of significance.
Hint: Use chi-square distribution, assume measured trait is normal, and evidence should be insufficient for rejecting null hypothesis.
In: Statistics and Probability
Z is a standard normal random variable, then k is ...
a. P(Z < k) = 0.92
b. P(Z > k) = 0.72
c. P(Z ≤ k) = 0.26
d. (A-Grade) P(−1 < Z < k) = 0.60
e. (A-Grade) P(k < Z < 1.7) = 0.57
f. (A-Grade) P(Z = k) = 0.00
In: Statistics and Probability