Consider the following data on x = weight (pounds) and y = price ($) for 10 road-racing bikes.
Brand | Weight | Price ($) |
---|---|---|
A | 17.8 | 2,100 |
B | 16.1 | 6,250 |
C | 14.9 | 8,370 |
D | 15.9 | 6,200 |
E | 17.2 | 4,000 |
F | 13.1 | 8,500 |
G | 16.2 | 6,000 |
H | 17.1 | 2,580 |
I | 17.6 | 3,500 |
J | 14.1 | 8,000 |
These data provided the estimated regression equation
ŷ = 28,243 − 1,418x.
For these data, SSE = 7,368,713.71 and SST = 51,100,800. Use the F test to determine whether the weight for a bike and the price are related at the 0.05 level of significance.
State the null and alternative hypotheses.
H0: β0 ≠ 0
Ha: β0 =
0H0: β1 ≠ 0
Ha: β1 =
0 H0:
β0 = 0
Ha: β0 ≠
0H0: β1 = 0
Ha: β1 ≠
0H0: β1 ≥ 0
Ha: β1 < 0
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Reject H0. We cannot conclude that the relationship between weight (pounds) and price ($) is significant.Do not reject H0. We conclude that the relationship between weight (pounds) and price ($) is significant. Do not reject H0. We cannot conclude that the relationship between weight (pounds) and price ($) is significant.Reject H0. We conclude that the relationship between weight (pounds) and price ($) is significant.
In: Statistics and Probability
The following regression model has been proposed to predict sales at a computer store.
Y=60-2X1+30X2+10X3
Where
X1= competitor’s previous day’s sales (in $1,000s)
X2=population within 1 mile (in 1,000s)
X3= 1 if radio advertising was used; 0 if otherwise
Y= Sales (in $1,000s)
In: Statistics and Probability
Data for a sample of 30 apartments in a particular neighborhood are provided in the worksheet. You want to see if there is a direct relationship between Size of the Apartment and Rent.
Rent | Size |
950 | 850 |
1500 | 1450 |
1150 | 1085 |
1400 | 1232 |
950 | 718 |
1700 | 1485 |
1550 | 1136 |
935 | 726 |
875 | 700 |
1050 | 956 |
1400 | 1100 |
1650 | 1500 |
1875 | 1985 |
1800 | 1674 |
1395 | 1223 |
1375 | 1225 |
1100 | 1300 |
1500 | 1345 |
1200 | 1150 |
1150 | 896 |
1100 | 1361 |
1150 | 1040 |
1200 | 755 |
800 | 1000 |
850 | 1200 |
500 | 650 |
900 | 1100 |
1000 | 900 |
1025 | 1000 |
900 | 953 |
Approximately what percentage of the variation in Rent is
explained by the regression model you derived?
Place your answer, rounded to 1 decimal place.
In: Statistics and Probability
In: Statistics and Probability
2. Solve the following linear program using the graphical solution procedure:
Max 8A + 5B s.t.
i. 1A ≤ 120
ii. 1B ≤ 150
iii. 2A + 4B ≤ 700 iv. A, B ≥ 0
In: Statistics and Probability
Hello,
I am in need of some assistance in interpreting the data for the two variables I did in a t-test for in Excel. Variable 1 is Relationship with Direct Supervisor and Variable 2 is the Workplace Happiness Rating. I am supposed to write a 125- to 175-word summary of my interpretation of the results of the t test.
t-Test: Two-Sample Assuming Equal Variances | ||
Variable 1 | Variable 2 | |
Mean | 2.5 | 7.4 |
Variance | 1.030612245 | 2 |
Observations | 50 | 50 |
Pooled Variance | 1.515306122 | |
Hypothesized Mean Difference | 0 | |
df | 98 | |
t Stat | -19.90287866 | |
P(T<=t) one-tail | 1.67192E-36 | |
t Critical one-tail | 1.660551217 | |
P(T<=t) two-tail | 3.34383E-36 | |
t Critical two-tail | 1.984467455 |
In: Statistics and Probability
5.90 Genetics of peas. According to genetic theory, the blossom color in the second generation of a certain cross of sweet peas should be red or white in a 3:1 ratio. That is, each plant has probability 3/4 of having red blossoms, and the blossom colors of separate plants are independent. (a) What is the probability that exactly 8 out of 10 of these plants have red blossoms? (b) What is the mean number of red-blossomed plants when 130 plants of this type are grown from seeds? (c) What is the probability of obtaining at least 90 red-blossomed plants when 130 plants are grown from seeds?
In: Statistics and Probability
Match the following
|
|
In: Statistics and Probability
a simple random sample of 28 filtered 100-mm cigarettes is obtained from a normally distributed population and the tar content of each cigarette is measured. the sample has a standard deviation of 0.16mg.use a 0.05 significance level to test the claim that the tar content of filtered 100-mm cigarettes has a standard deviation different from 0.20 mg, which is the standard deviation for unfiltered King size cigarettes
In: Statistics and Probability
Consider the following example. In a study reported in the California Journal of Nursing, nurses were asked to report their degree of job-related stress. They were asked 15 questions about their work and they responded on a 1-5 scale as the amount of stress they felt. These responses were added up in order to come up with a numeric measure of job stress (15 being the minimum stress and 95 the maximum stress). Below is the Table with 3 of the groups' data: LVN, RN, CNP. This is ANOVA. What do you make of this?
You can do this in SPSS or use the following: http://turner.faculty.swau.edu/mathematics/math241/materials/anova/.
LVN |
RN |
CNP |
81 |
43 |
65 |
41 |
63 |
48 |
68 |
60 |
57 |
69 |
52 |
91 |
54 |
54 |
70 |
62 |
77 |
67 |
76 |
68 |
83 |
56 |
57 |
75 |
61 |
61 |
53 |
65 |
80 |
71 |
64 |
50 |
54 |
69 |
37 |
72 |
83 |
73 |
65 |
85 |
84 |
58 |
75 |
58 |
58 |
In: Statistics and Probability
In an exactly 8 character long password where capital letters, small letters, and digits (0 to 9) must be used. Regardless of the order, how many passwords will use exactly 5 ones, 4 twos, and one Z?
In: Statistics and Probability
Supermarkets have limited the number of customers who are in their stores at any one time. At one particular store, store managers decide that 100 customers at one time is necessary to ensure social distancing guidelines mandated by the government. One store manger suspects that the number of customers is more than 100 so he counts the number of customers for a week at different times of the day and on different days of the week. Here are the numbers: 105, 98, 111, 123, 88, 95, 109.
(3pts) Using StatKey, find the p-value:
In: Statistics and Probability
In: Statistics and Probability
In: Statistics and Probability
Lester Hollar is vice president for human resources for a large manufacturing company. In recent years, he has noticed an increase in absenteeism that he thinks is related to the general health of the employees. Four years ago, in an attempt to improve the situation, he began a fitness program in which employees exercise during their lunch hour. To evaluate the program, he selected a random sample of eight participants and found the number of days each was absent in the six months before the exercise program began and in the six months following the exercise program. Below are the results.
Employee | Before | After |
1 | 5 | 3 |
2 | 5 | 6 |
3 | 6 | 2 |
4 | 7 | 7 |
5 | 4 | 3 |
6 | 5 | 2 |
7 | 7 | 1 |
8 | 6 | 2 |
Click here for the Excel Data File
At the 0.025 significance level, can he conclude that the number of absences has declined? Estimate the p-value.
State the decision rule for 0.025 significance level. (Round your answer to 3 decimal places.)
Compute the test statistic. (Round your answer to 3 decimal places.)
The p-value is
Between 0.01 And 0.025
Between 0.001 And 0.005
Between 0.005 And 0.01
State your decision about the null hypothesis.
Reject H0
Fail to reject H0
hypothesis. Reject H0 Fail to reject H0
In: Statistics and Probability