Trevor is interested in purchasing the local hardware/sporting goods store in the small town of Dove Creek, Montana. After examining accounting records for the past several years, he found that the store has been grossing over $850 per day about 50% of the business days it is open. Estimate the probability that the store will gross over $850 for the following. (Round your answers to three decimal places.)

(a) at least 3 out of 5 business days


(b) at least 6 out of 10 business days


(c) fewer than 5 out of 10 business days


(d) fewer than 6 out of the next 20 business days


If the outcome described in part (d) actually occurred, might it shake your confidence in the statement p = 0.50? Might it make you suspect that p is less than 0.50? Explain.

Yes. This is unlikely to happen if the true value of p is 0.50.Yes. This is likely to happen if the true value of p is 0.50.    No. This is unlikely to happen if the true value of p is 0.50.No. This is likely to happen if the true value of p is 0.50.

(e) more than 17 out of the next 20 business days


If the outcome described in part (e) actually occurred, might you suspect that p is greater than 0.50? Explain.

Yes. This is unlikely to happen if the true value of p is 0.50.Yes. This is likely to happen if the true value of p is 0.50.    No. This is unlikely to happen if the true value of p is 0.50.No. This is likely to happen if the true value of p is 0.50.

Using the data from the previous question on LDL cholesterol, you decide to test if the variance in LDL cholesterol of patients admitted to the hospital with a heart attack is the same as that of those who have not (the control). You use the R function var.test and obtain the following output.

   F test to compare two variances

data:  ldl.ha and ldl.cont

F = 7.683, num df = 9, denom df = 15,
   p-value = 0.0006501

alternative hypothesis: true ratio of
variances is not equal to 1

95 percent confidence interval:

2.460444 28.960945

sample estimates:

ratio of variances

          7.683258

What is your decision and conclusion (with respect to variation in LDL cholesterol levels) from the above R test output assuming an alpha level of 0.05? AND how does this help us beyond this test of the variance?

A certain virus infects one in every 400 people. A test used to detect the virus in a person is positive 85% of the time if the person has the virus and 5% of the time if the person does not have the virus. (This 5% result is called a false positive). Let A be the event "the person has the virus" and B be the event "the person tests positive".

1) Find the probability that A person has the virus given that they have tested positive, i.e. find P(A|B). (Round your answer to the nearest hundredth of a percent).

2 A person does not have the virus given that they test negative, i.e. find P(A'|B'). Round your answer to the nearest hundredth of a percent.

Hint: please answer this Questions with clear handwriting because I am not fluent im English .. I will be very thankfull for this

The data presented in the table below resulted from an experiment in which seeds of 4 different types were planted and the number of seeds that germinated within 4 weeks after planting was recorded for each seed type.

At the .05 level of significance, is the proportion of seeds that germinate dependent on the seed type?

• A.

  No, the proportion of seeds that germinate are not dependent on the seed type because the p-value = 0.0132.

• B.

  No, the proportion of seeds that germinate are not dependent on the seed type because the p-value = 0.0265.

• C.

  Yes, the proportion of seeds that germinate dependent on the seed type because the p-value = 0.0265.

• D.

  Yes, the proportion of seeds that germinate dependent on the seed type because the p-value = 0.0132.

Consider the data.

The estimated regression equation for these data is

ŷ = 75.75 − 3.25x.

(a)

Compute SSE, SST, and SSR using equations

SSE = Σ(y_i − ŷ_i)²,

SST = Σ(y_i − y)²,

and

SSR = Σ(ŷ_i − y)².

SSE = SST = SSR =

(b)

Compute the coefficient of determination

r².

(Round your answer to three decimal places.)

r²

=

Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.)

The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares line.The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line.     The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares line.The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line.

(c)

Compute the sample correlation coefficient. (Round your answer to three decimal places.)

In a survey of 1066 ​adults, a poll​ asked, "Are you worried or not worried about having enough money for​ retirement?" Of the 1066 ​surveyed, 566 stated that they were worried about having enough money for retirement. Construct a 95​% confidence interval for the proportion of adults who are worried about having enough money for retirement.

The average number of accidents at controlled intersections per year is 4.3. Is this average less for intersections with cameras installed? The 43 randomly observed intersections with cameras installed had an average of 3.7 accidents per year and the standard deviation was 1.47. What can be concluded at the αα = 0.01 level of significance?

Can you please explain the steps of how to obtain the P value and test statistic using a graphing calculator?

Your goal is to collect all 80 player cards in a game. The Player cards are numbered 1 through 80. High numbered cards are rarer/more valuable than lower numbered cards.

Albert has a lot of money to spend and loves the game. So every day he buys a pack for $100. Inside each pack, there is a random card. The probability of getting the n-th card is c(1.05)^-n, For some constant c. Albert buys his first pack on June 1st. What is the expected number of Player cards Albert will collect in June?(30 days)

a.) Find an exact, closed-form expression for c. (Answer should not include a summation symbol or integral sign).

b.)Find the expected number of unique Player cards Albert will collect in June. (Answer may include summation symbol or integral sign.

Chrysler Concorde: Acceleration Consumer reports stated that the mean time for a Chrysler Concorde to go from 0 to 60 miles per hour was 8.7 seconds.

a.) If you want to set up a statistical test to challenge the claim of 8.7 seconds, what would you use for the null hypothesis?

b.) The town of Leadville, Colorado, has an elevation over 10,000 feet. Suppose you wanted to test the claim that the average time to accelerate from 0 to 60 miles per hour is longer in Leadville (because of less oxygen). What would you use as an alternative hypothesis?

c.) Suppose a newer model year Chrysler Concorde came out and you wanted to test whether the average time to accelerate from 0 to 60 miles per hour had changed from the previous year. What would you use as an alternative hypothesis?

d.) Suppose you made an engine modification and you think the average time to accelerate from 0 to 60 miles per hour is reduced. What would you use as an alternative hypothesis?

e.) For each of the tests in parts (b), (c), and (d) , would the P-value area be on the left, on the right, or on both sides of the mean?

An engineer is designing a battery for use in a device that will be subjected to some extreme variations in temperature. The only design parameter that he can select at this point is the plate material for the battery, and he has three possible choices (1, 2, and 3). The engineer decides to test all three plate materials at three temperature levels (15°F, 70°F, and 125°F) because these temperatures are consistent with the product end-use environment. Four batteries are tested at each combination of plate material and temperature, and all 36 tests are run in completely random order. The response is the life of the battery in hours. Confirm that the interaction term is significant and then draw and interpret the Interaction Plot.

A manufacturer produces widgets whose lengths are normally distributed with a mean of 8.7 cm and standard deviation of 2.5 cm.

A. If a widget is selected at random, what is the probability it is greater than 9.1 cm.?

B. What is the standard deviation of the average of samples of size 34 ?

C. What is the probability the average of a sample of size 34 is greater than 9.1 cm? Round answer to four decimal places.

A genetic experiment involving peas yielded one sample of offspring consisting of

420

green peas and

134

yellow peas. Use a

0.05

significance level to test the claim that under the same​ circumstances,

24%

of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution.

The mean height of an adult giraffe is 18 feet. Suppose that the distribution is normally distributed with standard deviation 0.8 feet. Let X be the height of a randomly selected adult giraffe. Round all answers to 4 decimal places where possible.

a. What is the distribution of X? X ~ N(,)

b. What is the median giraffe height? ft.

c. What is the Z-score for a giraffe that is 21 foot tall?

d. What is the probability that a randomly selected giraffe will be shorter than 18.6 feet tall?

e. What is the probability that a randomly selected giraffe will be between 17.3 and 18.3 feet tall? f. The 75th percentile for the height of giraffes is ft.