Questions
Lot Price Data Lot Price is lot price in $1000s Lot Size is lot size in...

Lot Price Data
Lot Price is lot price in $1000s
Lot Size is lot size in 1000s of square feet
Mature Trees is the number of mature trees on the property
Distance from Water is the distance from the edge of property to the water in feet
Distance from Road is the distance from the main road to the center of the property in miles
Lot Price Lot Size Mature Trees Distance from Water Distance from Road
105.4 41.2 24 42 0.6
91.2 44.8 5 71 1.3
183.3 21.3 72 43 0.7
93.8 43.9 58 14 0.6
207.5 57.7 52 12 1.3
130.9 33.4 78 26 1.2
162.3 31.4 65 51 1.2
18.8 27.4 22 0 1.1
80.5 26.2 68 83 0.8
38.3 40.0 57 76 0.9
71.3 47.6 53 35 0.9
55.5 31.6 36 26 0.4
85.7 21.6 23 24 0.1
110.5 36.3 48 98 0.9
85.1 47.2 61 59 0.6
78.3 30.5 41 55 1.0
27.2 41.8 1 60 0.8
70.9 20.6 20 33 0.3
101.4 35.3 38 75 0.1
133.3 40.1 68 0 0.9
117.7 35.6 24 41 0.9
49.7 20.6 16 77 0.6
49.6 22.4 32 86 0.7
83.2 45.8 77 19 1.0
81.3 29.4 40 0 0.2
152.5 51.7 60 34 0.8
112.2 27.2 0 16 0.6
37.1 37.0 50 49 1.0
130.2 38.9 48 63 0.7
39.1 32.5 25 45 0.1
81.9 34.0 12 0 0.6
24.6 35.8 16 34 0.4
101.9 32.9 44 42 0.2
117.6 46.4 62 48 0.6
148.8 51.9 59 39 0.2
60.2 28.9 0 66 0.7
43.7 35.2 57 77 0.2
113.1 30.4 70 78 1.2
38.1 38.3 24 62 0.8
89.2 49.2 61 0 1.0
3.0 21.5 46 83 0.7
55.8 41.9 10 69 0.6
89.7 21.8 79 62 0.5
136.1 66.3 56 34 0.5
44.7 28.2 73 77 0.3
63.2 41.9 64 65 1.2
163.4 46.7 69 27 1.0
64.1 32.1 12 0 0.4
98.7 38.5 59 77 0.3
139.9 27.6 0 0 1.1
92.0 47.0 65 37 1.3
66.6 20.7 24 51 0.1
16.4 34.0 12 75 1.3
131.9 31.9 76 63 0.9
11.0 28.0 2 42 0.4
27.9 40.0 52 84 0.8
103.5 46.6 26 70 0.9
107.0 23.2 11 83 0.3
51.6 46.4 53 44 0.6
133.4 32.1 55 98 0.2

Use the Lot Price Data to run a regression in Excel. Your response variable is Lot Price, while the other four variables are all X variables in this regression. For the Mature Trees variable, the 95% confidence interval for the slope coefficient includes the hypothesized value of zero.

TRUE OR FALSE

In: Statistics and Probability

Question 1 An article in Technometrics by S. C. Narula and J. F. Wellington (“Prediction, Linear...

Question 1

An article in Technometrics by S. C. Narula and J. F. Wellington (“Prediction, Linear Regression, and a Minimum Sum of Relative Errors,” Vol. 19, 1977) presents data on the selling price (y) and annual taxes (x) for 24 houses. The taxes include local, school and county taxes. The data are shown in the following table.

Sale Price/1000 Taxes/1000
25.9 4.9176
29.5 5.0208
27.9 4.5429
25.9 4.5573
29.9 5.0597
29.9 3.8910
30.9 5.8980
28.9 5.6039
35.9 5.8282
31.5 5.3003
31.0 6.2712
30.9 5.9592
30.0 5.0500
36.9 8.2464
41.9 6.6969
40.5 7.7841
43.9 9.0384
37.5 5.9894
37.9 7.5422
44.5 8.7951
37.9 6.0831
38.9 8.3607
36.9 8.1400
45.8 9.1416

(a) Calculate the least squares estimates of the slope and intercept.

β^1=Enter your answer; beta1 (Round your answer to 3 decimal places.)

β^0=Enter your answer; beta0 (Round your answer to 2 decimal places.)

(b) Find the mean selling price given that the taxes paid are x = 5.3.

Enter your answer in accordance to the item b) of the question statement (Round your answer to 2 decimal places.)

(c) Calculate the fitted value of y corresponding to x = 5.0208 (observation #2). Find the corresponding residual.

y^=Enter your answer; the fitted value of y (Round your answer to 2 decimal places.)

y−y^=Enter your answer; the corresponding residual (Round your answer to 2 decimal places.)

Statistical Tables and Charts

Question Attempts: 0 of 2 used

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SUBMIT ANSWER

In: Statistics and Probability

The following data lists age (x, in years) and FICO credit score (y) for 15 random...

The following data lists age (x, in years) and FICO credit score (y) for 15 random credit card customers. At the 10% significance level, use Excel to test the claim that age and credit score are linearly related by specifying the slope estimate, p-value and final conclusion below. Do not round any intermediate calculations. Round your slope estimate answer to 2 decimal places. Round your p-value to 4 decimal places. Enter a "−" sign in front of any negative answer.

Slope estimate =

p-value =

Final conclusion:

The data does not support the claim that age and credit score are linearly related.

The data supports the claim that age and credit score are linearly related.

Age Credit Score

68 603

61 805

45 774

73 661

80 793

69 611

25 575

42 732

47 515

26 714

71 702

69 792

27 791

79 660

72 713

In: Statistics and Probability

3. A political candidate wants to estimate the mean income in her district. If the standard...

3. A political candidate wants to estimate the mean income in her district. If the standard deviation for incomes is known to be $10,000, how large a sample must she take if she wishes to be 99% certain that her estimate is within $2000 of the true mean?

4. A company that manufactures golf clubs wants to estimate the proportion of golfers who are left-handed. How large a sample must they take if they want to be 90% certain that their estimate is within 6% of the true proportion?

In: Statistics and Probability

What is Power ? Define it 2 ways. What are the 2 main uses for power?...

What is Power ? Define it 2 ways. What are the 2 main uses for power? Discuss how power is used for planning a research study. Why is it important to maximize power?What is the symbolic formula that shows this relationship?How strong should the power of a potential study be? How do researchers determine the power of a potential study?

In: Statistics and Probability

1. A random sample of 28 students at a particular university had a mean age of...

1. A random sample of 28 students at a particular university had a mean age of 22.4 years. If the standard deviation of ages for all university students is known to be 3.1 years,Find a 90% confidence interval for the mean of all students at that university. SHOW WORK

In: Statistics and Probability

The frequency distribution below shows the monthly expenditure on gasoline for a sample of 14 individuals....

The frequency distribution below shows the monthly expenditure on gasoline for a sample of 14 individuals.

Expenditure

Frequency

55 - 59

2

60 - 64

3

65 - 69

4

70 - 74

3

75 - 79

2

#1a). Compute the coefficient of variation.

#1b) The prior probabilities for events A1 and A2 are P (A1) = .40 and P (A2) = .60. It is also known that P (A1 n A2) = 0. Suppose P (B | A1) = .20 and P (B | A2) = .05.

#1bi). Are A1 and A2 mutually exclusive? Explain?

#1bii). Compute P(A1 n B) and P(A2 n B)

In: Statistics and Probability

The yearly salary (in thousands of dollars) for a small company are listed below. Find the...

The yearly salary (in thousands of dollars) for a small company are listed below. Find the mode, mean, median and population standard deviation and use the Empirical Rule to find a 95% confidence interval. 74 67 39 75 98 67 460 96

In: Statistics and Probability

determine if chocolate milk was as effective as other carbohydrate replacement drinks, nine male cyclists performed...

determine if chocolate milk was as effective as other carbohydrate replacement drinks, nine male cyclists performed an intense workout followed by a drink and a rest period. At the end of the rest period, each cyclist performed an endurance trial where he exercised until exhausted and time to exhaustion was measured. Each cyclist completed the entire regimen on two different days. On one day the drink provided was chocolate milk and on the other day the drink provided was a carbohydrate replacement drink. Data consistent with summary quantities appear in the table below. (Use a statistical computer package to calculate the P-value. Subtract the carbohydrate replacement times from the chocolate milk times. Round your test statistic to two decimal places, your df down to the nearest whole number, and the P-value to three decimal places.)

CyclistTime to Exhaustion (minutes)123456789Chocolate
Milk29.3247.3340.4348.6243.8435.4942.9739.4952.46Carbohydrate
Replacement23.3527.4117.6831.1140.0035.7639.3945.606.55


t= df= P=
Is there sufficient evidence to suggest that the mean time to exhaustion is greater after chocolate milk than after carbohydrate replacement drink? Use a significance level of 0.05.

YesNo    


In: Statistics and Probability

In a sample of 100 Oklahoma public schools, it was found that Oklahoma spends 8,097 dollars...

In a sample of 100 Oklahoma public schools, it was found that Oklahoma spends 8,097 dollars per pupil per year, with a standard deviation of 220 dollars. The population average of three surrounding states (Arkansas, Kansas, and Missouri) is 10,039 dollars. (these numbers are accurate – taken from most recent available data for 2016 https://ballotpedia.org/Public_education_in_Oklahoma.). Is per pupil spending for all Oklahoma schools less than the surrounding state population average? If you had to voice your concerns to your elected representative about per pupil spending in Oklahoma public schools, what would you tell them?

In: Statistics and Probability

1. Based on her own experiences in court, a prosecutor believes that some judges provide more...

1. Based on her own experiences in court, a prosecutor believes that some judges provide more severe punishments than other judges for people convicted of domestic violence. Five of the most recent domestic violence sentences (in years) handed down by three judges are recorded below.

Judge 1

Judge 2

Judge 3

1

3

1

1

2

5

3

4

2

2

3

1

2

4

1

Using this information, test the null hypothesis at the .05 level of significance that judges do not vary in the sentence lengths imposed on individuals convicted of domestic violence. In so doing, please: (1) identify the research and null hypotheses, (2) the critical value needed to reject the null, (3) the decision that you made upon analyzing the data, and (4) the conclusion you have drawn based on the decision you have made.

2. For a sample of 900 police officers at a local police department, a researcher believes there is a relationship between “number of arrests per month” and “police use of force.” Using the following data, test the null hypothesis at the .01 level of significance that police use of force does not differ by the number of arrests per month that an officer makes. In so doing, identify: (1) the research and null hypothesis, (2) the critical value needed to reject the null, (3) the decision that you made upon analyzing the data, and (4) the conclusion you have drawn based on the decision you have made.

                                                                 Number Of Arrests Per Month

            Use of Force                           One                  Two                 Three               Four or More               Total

            No Force                                  120                  100                 40                       120                                    380

            Force                                       120                  140                 100                       160                                    520_

                                                            240                  240                 140                       280                                   900

3. How is an Analysis of Variance (ANOVA) similar to and different from a t-test for two samples?

4. What statistical test would a researcher use to test the following research hypothesis: Individuals who report less favorable attitudes toward the police (measured as 1 = very favorable, 2 = somewhat favorable, 3 = somewhat not favorable, and 4 = not at all favorable) are more likely to be sentenced to higher security prisons (measured as 1 = minimum, 2 = medium, and 3 = maximum).

5. Why is it not possible to calculate a chi-square on the following hypothesis: Males have a higher number of total arrests than females?

6. Why is it impossible to calculate a negative F value when using an Analysis of Variance to test a hypothesis?

In: Statistics and Probability

The amount of cereal in fifteen boxes of Brand A breakfast cereal were found to have...

The amount of cereal in fifteen boxes of Brand A breakfast cereal were found to have a mean of 14 ounces and a standard deviation of 0.76 ounces. Construct a 90% confidence interval for the true standard deviation of the amount of cereal in Brand A boxes of breakfast cereal. Interpret your results

In: Statistics and Probability

oes Cable Video on Demand (VOD D4+) increase add effectiveness? A recent VOD study compared general...

oes Cable Video on Demand (VOD D4+) increase add effectiveness? A recent VOD study compared general TV and VOD D4+ audiences after viewing a brand add. Data were collected on whether the viewer indicated that the add made them want to visit the brand website. The results were:

Made me want to visit the brand website

Made me want to visit the brand website

Viewing Audience

Yes

No

VOD D4+

149

108

General TV

36

168

  1. Set up the null and alternative hypothesis to try to determine whether add impact is stronger following VOD D4+ viewing than following general TV viewing.
  2. Conduct the hypothesis test defined in (1), using the 0.05 level of significance.
  3. Does the results of your test in (2) make it appropriate to claim the ad impact is stronger following VOD D4+ than following general TV viewing?

In: Statistics and Probability

How much do wild mountain lions weigh? Adult wild mountain lions (18 months or older) captured...

How much do wild mountain lions weigh? Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains gave the following weights (pounds): 69 103 130 128 60 64 Assume that the population of x values has an approximately normal distribution. (a) Use a calculator with mean and sample standard deviation keys to find the sample mean weight x and sample standard deviation s. (Round your answers to one decimal place.) x = lb s = lb (b) Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.) lower limit lb upper limit lb

In: Statistics and Probability

oes Cable Video on Demand (VOD D4+) increase add effectiveness? A recent VOD study compared general...

oes Cable Video on Demand (VOD D4+) increase add effectiveness? A recent VOD study compared general TV and VOD D4+ audiences after viewing a brand add. Data were collected on whether the viewer indicated that the add made them want to visit the brand website. The results were: Made me want to visit the brand website Made me want to visit the brand website Viewing Audience Yes No VOD D4+ 149 108 General TV 36 168 Set up the null and alternative hypothesis to try to determine whether add impact is stronger following VOD D4+ viewing than following general TV viewing. Conduct the hypothesis test defined in (1), using the 0.05 level of significance. Does the results of your test in (2) make it appropriate to claim the ad impact is stronger following VOD D4+ than following general TV viewing

In: Statistics and Probability