In: Chemistry
Calculate [OH−] for each solution.
A. pH = 2.52
B. pH = 8.09
C. pH = 13.58
A. pH = 2.52
POH = 14-PH
= 14-2.52
POH = 11.48
-log[OH^-] = 11.48
[OH^-] = 10^-11.48 = 3.3*10^-12M
B. pH = 8.09
POH = 14-PH
= 14-8.09
POH = 5.91
-log[OH^-] = 5.91
[OH^-] = 10^-5.91
= 1.23*10^-6M
C. pH = 13.58
POH = 14-PH
= 14-13.58
= 0.42
-log[OH^-] = 0.42
[OH^-] = 10^-0.42
= 0.38M