Question

A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of 217 cars owned by students had an average age of 7.62 years. A sample of 252 cars owned by faculty had an average age of 6.266.26 years. Assume that the population standard deviation for cars owned by students is 2.67 years, while the population standard deviation for cars owned by faculty is 3.41 years. Determine the 99% confidence interval for the difference between the true mean ages for cars owned by students and faculty.

Step 1 of 3 :  

Find the point estimate for the true difference between the population means.

Answer 1

Answer:-

Given That:-

A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of 217 cars owned by students had an average age of 7.62 years. A sample of 252 cars owned by faculty had an average age of 6.266.26 years. Assume that the population standard deviation for cars owned by students is 2.67 years, while the population standard deviation for cars owned by faculty is 3.41 years.

Determine the 99% confidence interval for the difference between the true mean ages for cars owned by students and faculty.

Step 1 of 3 :  

Find the point estimate for the true difference between the population means?

Researcher compares the ages of cars owned by students and faculty at local state college

*Students:-

Sample size

average age year

Standard deviation

*Faculty :-

Sample size

average age years

Standard deviation years

Confidence Interval = 99%

level of significance = 0.01 [1-0.99=0.01]

* Point of estimate (or) Statistic
Z statistic  for two different means

1.Null hypothesis

2.Alternative hypothesis

Confidence interval at 99%

students:-

  

  

Interval

Faculty:-