In: Statistics and Probability
A researcher wants to examine the production capability of three manufacturing plants that utilize different production methods of the same part in order to select a plant as a supplier for a company. The effectiveness of each plant will be measured in the number of parts it can produce in an hour. Representative hourly production amounts are recorded from each plant over a period of 12 hours and provided to the researcher.
The results of each of the three plants are as follows:
| 
 Plant A  | 
 Plant B  | 
 Plant C  | 
| 
 131  | 
 141  | 
 108  | 
| 
 111  | 
 165  | 
 185  | 
| 
 165  | 
 174  | 
 190  | 
| 
 188  | 
 185  | 
 206  | 
| 
 175  | 
 172  | 
 175  | 
| 
 173  | 
 188  | 
 197  | 
| 
 188  | 
 145  | 
 186  | 
| 
 186  | 
 177  | 
 221  | 
| 
 145  | 
 162  | 
 214  | 
| 
 132  | 
 151  | 
 211  | 
| 
 128  | 
 147  | 
 214  | 
| 
 123  | 
 133  | 
 208  | 
The hypothesis being tested is:
H0: µ1 = µ2 = µ3
Ha: Not all means are not equal
| Mean | n | Std. Dev | |||
| 153.8 | 12 | 28.35 | Plant A | ||
| 161.7 | 12 | 18.09 | Plant B | ||
| 192.9 | 12 | 30.26 | Plant C | ||
| 169.4 | 36 | 30.61 | Total | ||
| ANOVA table | |||||
| Source | SS | df | MS | F | p-value | 
| Treatment | 10,293.06 | 2 | 5,146.528 | 7.55 | .0020 | 
| Error | 22,507.83 | 33 | 682.056 | ||
| Total | 32,800.89 | 35 | 
The p-value is 0.0020.
Since the p-value (0.0020) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that there is a significant difference between the groups.
The graph is:

The assumptions of ANOVA are violated.
Plant C would be recommended as a supplier because it has the highest hourly production amounts.
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