Question

Trace through the program and what the outputs will be. If there is an error explain what must be fixed and continue to trace through.

#include <iostream>
using namespace std;
void beans(int y, int& n, int size);
void spam(int& n, int& y);
int main(){
    int m = 7;
    int n = 4;
    cout<<"m is "<<m<<" n is "<<n<<endl;
    beans(n, m, 3);
    cout<<"m is "<<m<<" n is "<<n<<endl;
    spam(m, n);
    cout<<"m is "<<m<<" n is "<<n<<endl;
    beans(m, 2, n);
    cout<<"m is "<<m<<" n is "<<n<<endl;
    return 0;
}

void beans(int y, int& n, int size){
    y = n+size;
    n = 7+n;
}
void spam(int& n, int& y){
    int m = n+y;
    y=n;
    n=y+n;
}

Answer 1

When the function accepts a value using '&' , it is pointing to the address of variable whose value is passed. So changes will be directly reflected.

Therefore different value of m and n printed are

O/P	value of m	value of n
1	7	4
2	2i	14
3	28	14

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