In: Statistics and Probability
1.) The data below were gathered on a random sample of 5 basking sharks, swimming through the water and filter-feeding, i.e. passively letting the water bring food into their mouths.
Mean speeds for basking sharks |
|
Body Length |
Mean speed |
(meters) |
(meters/second) |
4.0 |
0.89 |
4.5 |
0.83 |
4.0 |
0.76 |
6.5 |
0.94 |
5.5 |
0.94 |
a) Construct the equation of the linear regression line. ^y (2 decimal places)
2.) A random sample of 20 death certificates in Hawaii gave the following data about the life span (in years) of Hawaii residents. Assume that lifespan is approximately normally distributed for this population.
72 77 68 69 81 85 93 97 56 75 19 71 78 86 94 47 83 66 84 27
Calculate a POINT ESTIMATE of the population mean of life span in Hawaii
1) Solution:
X | Y | XY | X^2 | Y^2 |
4 | 0.89 | 3.56 | 16 | 0.7921 |
4.5 | 0.83 | 3.735 | 20.25 | 0.6889 |
4 | 0.76 | 3.04 | 16 | 0.5776 |
6.5 | 0.94 | 6.11 | 42.25 | 0.8836 |
5.5 | 0.94 | 5.17 | 30.25 | 0.8836 |
n | 5 |
sum(XY) | 21.62 |
sum(X) | 24.50 |
sum(Y) | 4.36 |
sum(X^2) | 124.75 |
sum(Y^2) | 3.83 |
= a + bx
= 0.61 + 0.05X
2) Solution:
We have a sample .
Sample Size n = 20
We prepare a table.
X | X2 | |
72 | 5184 | |
77 | 5929 | |
68 | 4624 | |
69 | 4761 | |
81 | 6561 | |
85 | 7225 | |
93 | 8649 | |
97 | 9409 | |
56 | 3136 | |
75 | 5625 | |
19 | 361 | |
71 | 5041 | |
78 | 6084 | |
86 | 7396 | |
94 | 8836 | |
47 | 2209 | |
83 | 6889 | |
66 | 4356 | |
84 | 7056 | |
27 | 729 | |
Sum = | 1428 | 110060 |
Sample Mean = = 1428/20 = 71.4
Point Estimate of the population Mean = Sample Mean = 71.4