Question

A neighborhood fuel cell power plant is to be designed for an electric power output of 2000 kW with liquid– water product. Estimate the flow rates of hydrogen and oxygen during peak power production, assuming an 80% efficient power conditioner is used to convert DC to AC power and the fuel cell efficiency is 55%. What is the plant heat rate?

Answer 1

Given Data :-

As per Given Electric Power O/P = 2000 KW

Power Condition efficiency = 80 %

Fuel cell efficiency = 55 %

Find Out :- Flow rate of H₂ & O₂ & Plant Heat rate .

Solution :- First Naural Gas convert into H₂ Rich gas through Fuel process.

then in power section these H₂ gas generate DC power . after that through power condition it will be convert into AC power. i.e. output power. ( Given 2000 KW)

So we need to do reverse of this process to find out the H₂ flow rate.

so, DC power = 2000/ 0.8 =2500 KW.

Ans. 1 Flow Rate of H₂ & O₂ will be in proportional 100/140 . (By volumetric/ Min )

  H2 + 1 2 O2 ? H2O(g) ? ?fHH2O(g) = LHV = 241.82 kJ mol

The volume flow V? is calculated by the gas density ? or the molar gas volume V_o,

V? = m? ?.

Ans. 2 Plant Heat Rate :- (Fuel Burned x LHV ) / Output Energy

So, once we get Fuel burned flow rate then we can calculate plant heat rate by above formula.

For flow rate we need size of fuel tank.

Thanks.

i hope this will help you.