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CH4(g)+Cl2(g)=CH3Cl(g)+HCl(g) Kc=4.5*10^3 Initial Concentration of the reactants 0.0010 M calculate the equilibrium concentrations

CH4(g)+Cl2(g)=CH3Cl(g)+HCl(g)

Kc=4.5*10^3

Initial Concentration of the reactants 0.0010 M

calculate the equilibrium concentrations

Solutions

Expert Solution

   CH4(g)   +   Cl2(g)------->CH3Cl(g)+HCl(g)

I         0.001          0.001        0              0

C         -x               -x                   +x             +x

E      0.001-x       0.001-x             +x              +x

      Kc =   [CH3Cl][HCl]/[CH4]Cl2]

      4.5*10^3   = x*x/(0.00-x)(0.001-x)

   4500          = (x/(0.001-x))^2

    67             = x/0.001-x

67*(0.001-x) = x

        x   = 0.00098

      [CH4]   = 0.001-x = 0.001-0.00098   = 2*10^-5 M

      [Cl2]    = 0.001-x = 0.001-0.00098   = 2*10^-5 M

       [CH3Cl]   = x   = 0.00098M

      [HCl]        = x   = 0.00098 M

queen_honey_blossom answered 2 years ago
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