Question
In: Chemistry
CH4(g)+Cl2(g)=CH3Cl(g)+HCl(g) Kc=4.5*10^3 Initial Concentration of the reactants 0.0010 M calculate the equilibrium concentrations
CH4(g)+Cl2(g)=CH3Cl(g)+HCl(g)
Kc=4.5*10^3
Initial Concentration of the reactants 0.0010 M
calculate the equilibrium concentrations
Solutions
Expert Solution
CH4(g) + Cl2(g)------->CH3Cl(g)+HCl(g)
I 0.001 0.001 0 0
C -x -x +x +x
E 0.001-x 0.001-x +x +x
Kc = [CH3Cl][HCl]/[CH4]Cl2]
4.5*10^3 = x*x/(0.00-x)(0.001-x)
4500 = (x/(0.001-x))^2
67 = x/0.001-x
67*(0.001-x) = x
x = 0.00098
[CH4] = 0.001-x = 0.001-0.00098 = 2*10^-5 M
[Cl2] = 0.001-x = 0.001-0.00098 = 2*10^-5 M
[CH3Cl] = x = 0.00098M
[HCl] = x = 0.00098 M
queen_honey_blossom answered 2 years agoRelated Solutions
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