In: Statistics and Probability
In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find χ2α/2,df and χ21- α/2,df under the following scenarios. Use Table 3. (Round your answers to 3 decimal places.) χ2α/2,df and χ21- α/2,df .
A 95% confidence level with n = 18.
b. A 95% confidence level with n = 30.
c. A 99% confidence level with n = 18.
d. A 99% confidence level with n = 30.
a 95% confidence level with n = 18.
df = n-1 = 18-1 = 17
?=1-C=1-0.95=0.05
?/2=0.05/2=0.025
1-?/2=1-0.025=0.975
We refer to the values of df=17 and 0.025 and 0.975 across the top row of chi square table.
?2?/2,df= 30.191
?21- ?/2,df = 7.564
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b. A 95% confidence level with n = 30.
df = n-1 = 30-1 = 29
?=1-C=1-0.95=0.05
?/2=0.05/2=0.025
1-?/2=1-0.025=0.975
We refer to the values of df=29 and 0.025 and 0.975 across the top row of chi square table.
?2?/2,df= 45.722
?21- ?/2,df = 16.047
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c. A 99% confidence level with n = 18.
df = n-1 = 18-1 = 17
?=1-C=1-0.99=0.01
?/2=0.01/2=0.005
1-?/2=1-0.005=0.995
We refer to the values of df=17 and 0.005 and 0.995 across the top row of chi square table.
?2?/2,df= 35.718
?21- ?/2,df = 5.697
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d. A 99% confidence level with n = 30.
df = n-1 = 30-1 = 29
?=1-C=1-0.99=0.01
?/2=0.01/2=0.005
1-?/2=1-0.005=0.995
We refer to the values of df=29 and 0.005 and 0.995 across the top row of chi square table.
?2?/2,df= 52.336
?21- ?/2,df = 13.121