Question

In: Statistics and Probability

In order to construct a confidence interval for the population variance, a random sample of n...

In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find χ2α/2,df and χ21- α/2,df under the following scenarios. Use Table 3. (Round your answers to 3 decimal places.) χ2α/2,df and χ21- α/2,df .

A 95% confidence level with n = 18.

b. A 95% confidence level with n = 30.

c. A 99% confidence level with n = 18.

d. A 99% confidence level with n = 30.

Solutions

Expert Solution

a 95% confidence level with n = 18.

df = n-1 = 18-1 = 17

?=1-C=1-0.95=0.05

?/2=0.05/2=0.025

1-?/2=1-0.025=0.975

We refer to the values of df=17 and 0.025 and 0.975 across the top row of chi square table.

?2?/2,df= 30.191

?21- ?/2,df = 7.564

-------------------------------------------------------------------------------------------------------------------------------------------

b. A 95% confidence level with n = 30.

df = n-1 = 30-1 = 29

?=1-C=1-0.95=0.05

?/2=0.05/2=0.025

1-?/2=1-0.025=0.975

We refer to the values of df=29 and 0.025 and 0.975 across the top row of chi square table.

?2?/2,df= 45.722

?21- ?/2,df = 16.047

-------------------------------------------------------------------------------------------------------------------------------------------

c. A 99% confidence level with n = 18.

df = n-1 = 18-1 = 17

?=1-C=1-0.99=0.01

?/2=0.01/2=0.005

1-?/2=1-0.005=0.995

We refer to the values of df=17 and 0.005 and 0.995 across the top row of chi square table.

?2?/2,df= 35.718

?21- ?/2,df = 5.697

-------------------------------------------------------------------------------------------------------------------------------------------

d. A 99% confidence level with n = 30.

df = n-1 = 30-1 = 29

?=1-C=1-0.99=0.01

?/2=0.01/2=0.005

1-?/2=1-0.005=0.995

We refer to the values of df=29 and 0.005 and 0.995 across the top row of chi square table.

?2?/2,df= 52.336

?21- ?/2,df = 13.121


Related Solutions

In order to construct a confidence interval for the population variance, a random sample of n...
In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find χ2α/2,df and χ21-α/2,df under the following scenarios. (Round your answers to 3 decimal places. You may find it useful to reference the appropriate table: chi-square table or F table) χ2α/2,df χ21-α/2,df a. A 90% confidence level with n = 20. b. A 90% confidence level with n = 43. c. A 99%...
In order to construct a confidence interval for the population variance, a random sample of n...
In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find χ2α/2,df and χ21- α/2,df under the following scenarios. (Round your answers to 3 decimal places. You may find it useful to reference the appropriate table: chi-square table or F table) χ2α/2,df χ21- α/2,df a. A 95% confidence level with n = 18. b. A 95% confidence level with n = 30. c....
n order to construct a confidence interval for the population variance, a random sample of n...
n order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find χ2α/2,df and χ21-α/2,df under the following scenarios. (Round your answers to 3 decimal places. You may find it useful to reference the appropriate table: chi-square table or F table) χ2α/2,df χ21-α/2,df a. A 90% confidence level with n = 11. b. A 90% confidence level with n = 42. c. A 95%...
Construct a 99% confidence interval on the population variance and the population standard deviation for the...
Construct a 99% confidence interval on the population variance and the population standard deviation for the data listed below: 91.8, 112.1, 138.3, 90.6, 136.6, 113.6, 101.5, 123.6, 81.4, 119.2, 111.4, 89.4, 110.5, 80.5, 94.8, 117.0, 105.7, 146.6, 138.6, 99.9, 106.6
Construct a 95% confidence interval for the population standard deviation of a random sample of 15...
Construct a 95% confidence interval for the population standard deviation of a random sample of 15 crates which have a mean weight of 165.2 points and a standard deviation of 12.9 pounds. Assume the population is normallyn distributed. A. 9.9, 18.8 B. 9.4, 20.3 Please show work.
Determine the sample size n needed to construct a 95?% confidence interval to estimate the population...
Determine the sample size n needed to construct a 95?% confidence interval to estimate the population proportion for the following sample proportions when the margin of error equals 55?%. a. p? = 0.50 b. p = 0.60 c. p = 0.70
Determine the sample size n needed to construct a 90​% confidence interval to estimate the population...
Determine the sample size n needed to construct a 90​% confidence interval to estimate the population mean when sigma equals 67 and the margin of error equals 10. n=???????
Determine the sample size n needed to construct a 95​% confidence interval to estimate the population...
Determine the sample size n needed to construct a 95​% confidence interval to estimate the population mean for the following margins of error when sigma equals 67. ​a) 25 ​b) 40 ​c) 50
Determine the sample size n needed to construct a 90​% confidence interval to estimate the population...
Determine the sample size n needed to construct a 90​% confidence interval to estimate the population proportion when p over bar equals 0.64 and the margin of error equals 7​%. n=???
Determine the sample size n needed to construct a 99​% confidence interval to estimate the population...
Determine the sample size n needed to construct a 99​% confidence interval to estimate the population proportion when p over bar equals 0.62 and the margin of error equals 7​%. n=?????
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT