Calculate the fraction of nitrous acid deprotonated if the solution concentration is 0.241 M. The acid...

Calculate the fraction of nitrous acid deprotonated if the solution concentration is 0.241 M. The acid dissociation constant of nitrous acid is 3.0 x 10^-8.

How do you solve for x?

Expert Solution

HNO2(aq) -------------> H^+ (aq) + NO2^- (aq)

I 0.241 0 0

C -x +x +x

E 0.241-x +x +x

Ka = [H^+][NO2^-]/[HNO2]

3*10^-8 = x*x/(0.241-x)

3*10^-8 *(0.241-x) = x^2

x^2+3*10^-8x -7.953*10^-8 = 0

x = -b-b^2-4ac/2a x= -b+b^2-4ac/2a

x = 8.5*10^-5

[H^+] = x = 8.5*10^-5 M

the fraction of nitrous acid deprotonated = [H^+]*100/initial concentration of acid

= 8.5*10^-5 *100/0.241 = 0.0353%

queen_honey_blossom answered 2 years ago

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