Question

In: Biology

If the oxidation of glucose can produce flames, as seen when roasting a marshmallow over a...

If the oxidation of glucose can produce flames, as seen when roasting a marshmallow over a campfire, why don’t we risk internal burns when we swallow a marshmallow and oxidize its glucose with cellular respiration?

Oxidation is not taking place. The marshmallow is being reduced.
The lining of our stomach prevents burning food from causing damage to our bodies
Digestion of the marshmallow is an endergonic process, therefore, no energy is released
Cellular respiration releases the energy from the glucose in small increments, rather than all at once.

What does an enzyme change in a reaction?

the ΔG.
the activation energy.
the types of products.
the first law of thermodynamics.

Which of the following does NOT describe ATP hydrolysis?

often coupled to a reaction that has a positive ΔG      
exergonic
spontaneous
having a positive ΔG

Solutions

Expert Solution

1- In case of burning a marshmallow the all the energy is released at once without any control. In case of cellular respiration, energy is released in step by step manner so that the releases energy can be utilized in the generation of ATP.

So correct answer is option D- Cellular respiration releases the energy from the glucose in small increments, rather than all at once

2- Enzyme catalyze the chemical reaction by decreasing the activation energy. The enzyme lowers the activation energy so that reactant can be converted into the product with less amount of energy required from outside.

So the answer is option B- activation energy.

3- ATP when hydrolase releases energy so ATP hydrolysis is an endergonic process.

Any reaction which has negative delta G is spontaneous and hydrolysis of ATP has negative delta G. So ATP hydrolysis is a spontaneous process.

ATP hydrolysis is a reaction which has negative delta G. It can be coupled with the reaction which has positive delta G so that the overall reaction have negative delta G.

So option D- having a positive ΔG is not correct.


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