Question

In: Statistics and Probability

According to a recent by the CDC, 37% of Americans said that they'd eaten fast food...

According to a recent by the CDC, 37% of Americans said that they'd eaten fast food within the past 24 hrs with 7.8% of Americans being considered High income AND have eaten fast food within the past 24HRS. It's also know that 21.1% of Americans are High Income, 49.9% are Middle Income, and the rest of individuals are Low Income. Finally, 18.0% of Americans are considered Middle Income AND have eaten fast food within the past 24 HRS.
A) calculated the probability that someone has eaten fast food in the last 24 HRS given that they're Middle Income.
B) calculated the probability that someome has eaten fast food or is low income
C) Are the events of eating fast food and income independent? If not, please briefly explain how the events are related

Solutions

Expert Solution

Here,

P[ eaten fast food within the past 24 hrs] = P[E] = 0.37

P[High Income AND eaten fast food] = P[H and E] = 0.078

P[  Middle Income AND eaten fast food ] = P[M and E] = 0.18

P[High Income]=P[H] =0.211

P[Middle Income]=P[M] =0.499

P[Low Income]= P[L] = 1- 0.211 - 0.499 = 0.29

A)

Note: In case of dependent events , the probability that both events occur simultaneously is:

P(A and B)=P(A)⋅P(B | A) (Conditional probability)

So, probability that someone has eaten fast food in the last 24 HRS given that they're Middle Income.

P[E/H] = P[H and E] / P[H] = 0.078 / 0.211 = 0.3697

B) The probability that someome has eaten fast food or is low income

P[E or L] = P[E] + P[L] - P[E and L] = P[E] + P[L] - P[E].P[L]

= 0.37 + 0.29 + 0.37*0.29

= 0.66 - 0.1073 = 0.5527

C) YES

Two events are said to be independent, when the occurrence of one event cannot control the occurrence of other. For independent events P(A and B) = P(A) P(B)

Here the  the events of eating fast food and income are clearly independent.


Related Solutions

In a survey of 1,000 adults in a country, 722 said that they had eaten fast...
In a survey of 1,000 adults in a country, 722 said that they had eaten fast food at least once in the past month. Create a 95% confidence interval for the population proportion of adults who ate fast food at least once in the past month. Use Excel to create the confidence interval, rounding to four decimal places.
In a study of the accuracy of fast food? drive-through orders, one restaurant had 37 37...
In a study of the accuracy of fast food? drive-through orders, one restaurant had 37 37 orders that were not accurate among 331 331 orders observed. Use a 0.05 0.05 significance level to test the claim that the rate of inaccurate orders is equal to? 10%. Does the accuracy rate appear to be? acceptable?
In a random sample of 100 adult Americans who did not attend college, 37 said they...
In a random sample of 100 adult Americans who did not attend college, 37 said they believe in extraterrestrials. In a random sample of 100 adult Americans who did attend college, 47 said they believe in extraterrestrials. At the 1% level of significance, does this indicate that the proportion of people who did not attend college and believe in extraterrestrials is less than the proportion of people who did attend college and believe in extraterrestrials? State the null and alternate...
According to the CDC, more than half of all Americans consumed a supplement in 2012. Supplements...
According to the CDC, more than half of all Americans consumed a supplement in 2012. Supplements are common in our culture, and many people think they need to consume a supplement to be healthy. Are supplements safe? In this forum, we will investigate vitamin and mineral supplements. Using your favorite search engine, find a vitamin and mineral supplement and evaluate it. In your initial forum post, discuss the following: What is the cost of these supplements? How do the amounts...
According to a Gallup Poll, 18% of Americans surveyed said that they had gained “a lot”...
According to a Gallup Poll, 18% of Americans surveyed said that they had gained “a lot” of weight in the past five years. Assume that this result is true for the current population of Americans. A random sample of 14 Americans is selected. a.Find the probability that in a random sample of 14 Americans, the number who will say they have gained “a lot” of weight in the past five years is at most 2. Draw a distribution b. Find...
In a study of the accuracy of fast food​ drive-through orders, one restaurant had 37 orders...
In a study of the accuracy of fast food​ drive-through orders, one restaurant had 37 orders that were not accurate among 305 orders observed. Use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to​ 10%. Does the accuracy rate appear to be​ acceptable? Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is? ​(Round to two decimal places as​ needed.) Identify the​ P-value for this hypothesis...
2. According to a recent study, 40% of Americans believe that marriage is necessary for a...
2. According to a recent study, 40% of Americans believe that marriage is necessary for a happy life. (a) Suppose a random sample of 500 Americans is asked about their opinion on mar- riage. What is the sampling distribution of pˆ, the proportion who believe marriage is necessary for a happy life? Verify all necessary assumptions. (b) What is the probability that in the random sample of 500 Americans, between 40% and 43% believe marriage is necessary for a happy...
In a recent statistics survey, 37 out of 129 randomly sampled college students said they get...
In a recent statistics survey, 37 out of 129 randomly sampled college students said they get enough sleep. Penn State conducted a much larger scale study a few years ago and found that 40% of college students got enough sleep. Is the lower percentage among college students in the recent study due to chance or is it signifcantly lower than the Penn State study? Determine the alpha level for this study.
According to AARP, in 2008, 49% of all annual expenditure on restaurant food was by Americans...
According to AARP, in 2008, 49% of all annual expenditure on restaurant food was by Americans age 50+. In fact AARP claims the average annual expenditure for Americans age 50+ on restaurant food in 2008 was $1960. Suppose a 2015 study randomly sampled 42 Americans age 50+ and found an average annual expenditure on restaurant food of $2145 with a standard deviation of $600. Is there reason to believe that the average annual expenditure for Americans age 50+ on restaurant...
1. One out of four Americans over age 55 has eaten pizza for breakfast. P(Eaten Pizza)...
1. One out of four Americans over age 55 has eaten pizza for breakfast. P(Eaten Pizza) = 0.25. If a sample of 10 Americans over the age of 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast. Use the binomial formula.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT