In: Accounting
A young college student John, decides to make computers in a small workshop. A single computer consists of the following components, that cost the amounts given: Components Cost in $ per computer Picture tube for monitor: 20 Bare chassis 15 Passive resistors 25 Active IC’s 70 Cabinet 40 Speakers /accessories 20 Other Costs and Expenses: In addition to the above part and component costs: John has one engineer (whom he cannot do without), and pays $ 24,000 a year for his services. This engineer has been employed on a five year contract, that cannot be breached. John also has rented the workshop with a ‘lease’ that cannot be broken, paying $6,000 a year as rent. Assume John’s venture has no other annual costs. As initial investment, John has also spent $ 100,000 on manufacturing plant and equipment that should be usable for a period of five years
Q4: What should John price the computer at if he wishes to make a profit of 10%, as a percentage of sales. [ This is also simply referred to as markup or markup on sales]. John is selling 300 computers in a year
Q7: Assume the production level of 1400 computers per year. John finds that he has to maintain an average component inventory equal to 2 month’s production, finished goods in warehouses amount to three month’s production, payments are made by dealers and distributors two and a half months after purchase. The annual rate of interest relevant to John’s business is 10%. Now what is the break even price for John?
Q8: John plans to introduce a product in the Florida market – to do this he expects to invest $ 300,000 on a building that has a resale value of $ 200,000 after five years, his revenues are expected to be $ 100,000 per year and costs are $40,000 by the end of the first year, $ 45,000 for the next year, and $30,000 per year for the remaining three years. Calculate the NPV of the Florida project, if the discount rate or rate of interest is 10% annually.
4..Components Cost per computer | |
Picture tube for monitor | 20 |
Bare chassis | 15 |
Passive resistors | 25 |
Active IC's | 70 |
Cabinet | 40 |
Speakers/accessories | 20 |
Total components (variable) cost/unit | 190 |
Other fixed costs: | |
Engineer's salary(24000/300) | 80 |
Rent(6000/300) | 20 |
Equipment depn.(100000/5/300) | 67 |
Total fixed cost/unit | 167 |
Total cost/unit | 357 |
Add: Mark-up(357/90*10) | 40 |
Selling price | 396 |
ANSWER: | |
If he wishes to make a profit of 10%, as a percentage of sales | |
John should price the computer at $ 396 | |
(rounding-of diff. may pl. be excepted) |
7… | ||
Components Inventory reqd. | 1400/12*2*190= | 44333 |
Finished goods inventory reqd. | (1400/12*3*357)= | 124950 |
Accounts receivables | (300*396/12*2.5)= | 24750 |
Total amt. locked up in current assets | 194033 | |
Opportunity cost of interest lost on the above funds | (194033*10%)= | 19403 |
Total production (units) | 1400 | |
Cost/unit | 19403/1400= | 14 |
So, | ||
Total fixed cost now comes to | 167+14= | 181 |
So, the Break-even price will be | ||
Variable cost/unit+Contribution/unit reqd. to cover the fixed costs | ||
ie. 190+181= | ||
371 | ||
So, the ANSWER is: | ||
Break even price for John= $ 371 |
8.NPV of the Florida project: |
NPV=Initial investment+PV of the 5 yrs.' revenues-individual PVs of the 5 yrs.' costs+PV of the resale value at end yr.5 |
-300000+(100000*(1-1.1^-5)/0.1)-(40000/1.1^1)-(45000/1.1^2)-(30000/1.1^3)-(30000/1.1^4)-(30000/1.1^5)+(200000/1.1^5)= |
68052 |