In: Chemistry
Determine the yield of your crude product (in grams and in %)
reagent 1: m-toluoyl chloride MW: 154.60 g Density: 1.173 Quantity 0.90g
reagent 2: diethylamine: MW: 73.14g Density: 0.707 Quantity: 3.50mL
product: MW: 191.27g Density: 0.996 Quantity: 0.251 g
1 mol of m-toluoyl chloride = 154.60 g
0.90 g of m-toluoyl chloride = 0.90/154.60 = 0.0058 mol
3.50 mL of diethylamine corresponds to 0.707x3.50=2.47g (m=dxv)
2.47 g of diethylamine = 2.47/73.14 = 0.0338 mol
mol equivalent of diethylamine = 0.0338/0.0058 = 5.83
since the limiting reagent is m-toluoyl chloride, which is 0.0058 mol, the product should also be 0.0058 mol according to the stoichiometry of the reaction.
0.0058 mol of product in grams = 0.0058 x 191.27 = 1.109 g
so the theoretical yield is 1.109 g
the given practical yiled is 0.251 g
% practical yield = practical yield/theoretical yield x100
=0.251/1.109 x 100
= 0.2263 x100
= 22.63
hence the pracctical yield is 22.63%