In: Statistics and Probability
A report states that the cost of repairing a hybrid vehicle is falling even while typical repairs on conventional vehicles are getting more expensive. The most common hybrid repair, replacing the hybrid inverter assembly, had a mean repair cost of
$3 comma 9273,927
in 2012. Industry experts suspect that the cost will continue to decrease given the increase in the number of technicians who have gained expertise on fixing gas-electric engines in recent months. Suppose a sample of
100100
hybrid inverter assembly repairs completed in the last month was selected. The sample mean repair cost was
$3 comma 8603,860
with the sample standard deviation of
$300300.
Complete parts (a) and (b) below.
a. Is there evidence that the population mean cost is less than
$3 comma 9273,927?
(Use a
0.050.05
level of significance.)
State the null and alternative hypotheses.
H0:
muμ
▼
not equals≠
greater than or equals≥
greater than>
less than or equals≤
less than<
equals=
$nothing
H1:
muμ
▼
equals=
greater than or equals≥
greater than>
less than<
less than or equals≤
not equals≠
$nothing
(Type integers or decimals.)
Find the test statistic for this hypothesis test.
test
statisticequals=nothing
(Round to two decimal places as needed.)
The critical value(s) for the test statistic is(are)
nothing.
(Round to two decimal places as needed. Use a comma to separate answers as needed.)
Is there sufficient evidence to reject the null hypothesis using
alphaαequals=0.050.05?
A.
RejectReject
the null hypothesis. There is
sufficientsufficient
evidence at the
0.050.05
level of significance that the population mean cost is less than
$3 comma 9273,927.
B.
Do not rejectDo not reject
the null hypothesis. There is
insufficientinsufficient
evidence at the
0.050.05
level of significance that the population mean cost is greater than
$3 comma 9273,927.
C.
RejectReject
the null hypothesis. There is
sufficientsufficient
evidence at the
0.050.05
level of significance that the population mean cost is greater than
$3 comma 9273,927.
D.
Do not rejectDo not reject
the null hypothesis. There is
insufficientinsufficient
evidence at the
0.050.05
level of significance that the population mean cost is less than
$3 comma 9273,927.
b. Determine the p-value and interpret its meaning.
The p-value is
nothing.
(Round to three decimal places as needed.)
What does this p-value mean given the results of part (a)?
A.The p-value is the probability that the actual mean cost is
$3 comma 8603,860
or less.
B.The p-value is the probability that the actual mean cost is
$3 comma 9273,927
or less given the sample mean cost is
$3 comma 8603,860.
C.The p-value is the probability that the actual mean cost is more than
$3 comma 8603,860.
D.The p-value is the probability of getting a sample mean cost of
$3 comma 8603,860
or less if the actual mean cost is
$3 comma 9273,927.
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
Ho: μ = 39273927
Ha: μ < 39273927
This corresponds to a left-tailed test, for which a t-test for one mean, with unknown population standard deviation will be used.
(2) Rejection Region: Based on the information provided, the significance level is α=0.05, and the critical value for a left-tailed test is tc=−1.66.
The rejection region for this left-tailed test is R=t:t<−1.66
(3) Test Statistics
The t-statistic is computed as follows:
tcritical value=-1.66
(4) Decision about the null hypothesis
CRITICAL VALUE APPROACH: Since it is observed that t=−2.95<tc=−1.66, it is then concluded that the null hypothesis is rejected.Therefore, there is enough evidence to claim that the population mean μ is less than 3927, at the 0.05 significance level.
Using the P-value approach: The p-value is p=0.002, and since p=0.002<0.05, it is concluded that the null hypothesis is rejected. It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the population mean μ is less than 3927, at the 0.05 significance level.
The P value is the probability that the actual mean cost is more than $ 3750.