In: Statistics and Probability
The weights of ripe watermelons grown at a farm are normally distributed with a mean of 12.2 pounds and a standard deviation of 1.2 pounds.
What did you use to answer this question, the tables or the calculator? Make sure your work confirms your answer.
a)
µ = 12.2
σ = 1.2
P ( X ≥ 13.5 ) = P( (X-µ)/σ ≥ (13.5-12.2) /
1.2)
= P(Z ≥ 1.08 ) = P( Z <
-1.083 ) = 0.1393
(answer)
b)
P( X ≤ 12 ) = P( (X-µ)/σ ≤ (12-12.2)
/1.2)
=P(Z ≤ -0.17 ) =
0.4338 (answer)
c)
we need to calculate probability for ,
P ( 11.3 < X <
12 )
=P( (11.3-12.2)/1.2 < (X-µ)/σ < (12-12.2)/1.2 )
P ( -0.750 < Z <
-0.167 )
= P ( Z < -0.167 ) - P ( Z
< -0.75 ) =
0.4338 - 0.2266 =
0.2072 (answer)
d)
P(X≤x) = 0.92
Z value at 0.92 =
1.4051 (excel formula =NORMSINV(
0.92 ) )
z=(x-µ)/σ
so, X=zσ+µ= 1.405 *
1.2 + 12.2
X = 13.9 (answer)