In: Statistics and Probability
A research group conducted an extensive survey of 2857 wage and salaried workers on issues ranging from relationships with their bosses to household chores. The data were gathered through hour-long telephone interviews with a nationally representative sample. In response to the question, "What does success mean to you?" 1470 responded, "Personal satisfaction from doing a good job." Let p be the population proportion of all wage and salaried workers who would respond the same way to the stated question. Find a 90% confidence interval for p. (Round your answers to three decimal places.)
lower limit | |
upper limit |
n = 2857
x = 1470
(Round to 4 decimal)
90% confidence interval for population proportion (p):
Confidence level = c= 0.90
Lower limit =
Upper limit =
Where
Where Zc is z critical for (1+c) /2 = (1+0.90)/2 = 0.95
Zc = 1.645 (From statistical table, average of 1.64 and 1.65)
E = 0.0154 (Round to 4 decimal)
Lower limit = 0.5145 - 0.0154 = 0.4991
Upper limit = 0.5145 + 0.0514 = 0.5659
Lower limit = 0.4991
Upper limit = 0.5659