In: Statistics and Probability
A research group conducted an extensive survey of 3155 wage and salaried workers on issues ranging from relationships with their bosses to household chores. The data were gathered through hour-long telephone interviews with a nationally representative sample. In response to the question, "What does success mean to you?" 1499 responded, "Personal satisfaction from doing a good job." Let p be the population proportion of all wage and salaried workers who would respond the same way to the stated question. Find a 90% confidence interval for p. (Round your answers to three decimal places.)
A)find the upper limit
B) Find thelower limit
please post all steps. do not use excel. please try to explain each step so I can learn how to do this.
I have answered the question below
Please up vote for the same and thanks!!!
Do reach out in the comments for any queries
Answer:
Given
n = 3155
x = 1499
phat = x/n = 0.47512
90% confidence z = 1.645
= 0.4751 +- 1.645*sqrt(0.4751*(1-0.4751)/3155))
= 0.4751 +- 0.014625
= >
LL = 0.4605
UL = 0.4897