In: Math
Find two numbers with the condition that their sum, 8 is four times their difference?
Suppose x and y be the two numbers, with x being greater of the two.
From question:
x + y = 8
x = 8 - y Eq. I
and 4 (x - y) = x + y
⇒ 4x - 4y = x + y
⇒ 3x - 5y = 0 Eq. II
Substitute value of x from Eq. I in Eq. II:
3 ( 8 - y) - 5y = 0
⇒ 24 - 3y - 5y = 0
⇒ 24 - 8y = 0
⇒ 8y = 24
⇒ y = 24/8 =3
Substitute y = 3 in Eq. I:
x = 8 - 3 = 5
Thus, the two numbers satisfying the conditions are: 5 and 3
The two numbers satisfying the conditions are: 5 and 3.