In: Statistics and Probability
Potatoes - Samples: Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.2 ounces and a standard deviation of 1.2 ounces.
(a) If 4 potatoes are randomly selected, find the probability that the mean weight is less than 9.5 ounces. Round your answer to 4 decimal places.
(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.5 ounces. Round your answer to 4 decimal places.
Solution :
Given that ,
mean =
= 8.2
standard deviation =
= 1.2
(a)
=
/
n = 1.2 /
4 = 0.6
P(
< 9.5) = P((
-
) /
< (9.5 - 8.2) / 0.6)
= P(z < 2.1667)
= 0.9849
Probability = 0.9849
(b)
=
/
n = 1.2 /
6 = 0.4899
P(
> 9.5) = 1 - P(
< 9.5)
= 1 - P[(
-
) /
< (9.5 - 8.2) / 0.4899]
= 1 - P(z < 2.6536)
= 1 - 0.996
= 0.004
Probability = 0.004