In: Math
Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 8.2 ounces and a standard deviation of 1.3 ounces.
(a) If 4 potatoes are randomly selected, find the probability that the mean weight is less than 10.0 ounces. Round your answer to 4 decimal places.
(b) If 6 potatoes are randomly selected, find the probability that the mean weight is more than 9.6 ounces. Round your answer to 4 decimal places.
Solution :
Given that ,
mean = = 8.2
standard deviation = = 1.3
a) n = 4
= 8.2 and
= / n = 1.3 / 4 = 0.65
P( < 10.0) = P(( - ) / < (10.0 - 8.2) / 0.65)
= P(z < 2.7692)
Using standard normal table,
=0.9972
Probability = 0.9972
b) n = 6
= 8.2 and
= / n = 1.3 / 6 = 0.5307
P( > 9.6) = 1 - P( < 9.6)
= 1 - P(( - ) / < (9.6 - 8.2) / 0.5307)
= 1 - P(z < 2.6380)
Using standard normal table,
= 1 - 0.9958
= 0.0042
Probability = 0.0042