Question
In: Chemistry
a mixture of 15.0g of Ne and 35.0g Ar have a total pressure of 3.4atm. What...
a mixture of 15.0g of Ne and 35.0g Ar have a total pressure of 3.4atm. What is the partial pressure of Ne ?
Solutions
Expert Solution
no of moles of Ne nNe = W/G.A.Wt
= 15/20
= 0.75 moles
no of moles of Ar nAr = W/G.A.Wt
= 35/40
= 0.875moles
mole fraction of Ne XNe = nNe/nNe+nAr
= 0.75/0.75+0.875
= 0.75/1.625
= 0.46
partial pressure of Ne = mole fraction of Ne * total pressure
= 0.46*3.4 = 1.564atm >>>>>answer
queen_honey_blossom answered 2 years agoRelated Solutions
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