Question

In: Statistics and Probability

. (1) A man has a 4-sided (tetrahedral) die, with four faces, 1, 2, 3, and...

. (1) A man has a 4-sided (tetrahedral) die, with four faces, 1, 2, 3, and 4. He rolls it 12 times. (a) Given that for each roll of the die, the probability of rolling a 4 is 1/4 and the probability of not doing so is 3/4, compute the following probabilities P(x = x0),where x is the number of times that the man rolls a 4 among the 12 trials. (b) What is the average value of x? What is the standard deviation? (c) Which possible value of x has the highest likelihood of occurring? (2) IQ scores in America, by definition, are normally distributed, with 100 points being the mean IQ and the standard deviation being 10 points. (a) Suppose a person has an IQ of 115. What percentage of the population is expected to have a higher IQ than this person? (b) Now suppose a person has an IQ of 75. What percentage of the population is expected to have a lower IQ than this person? (c) An individual’s IQ was claimed to have jumped from 83 to 212 after a procedure. (An IQ of 212 is not possible, given that most tests only can assign scores of at most 170.) What percentage of the population, were the claim not false, would be between the first score and the second?

Solutions

Expert Solution

1) the probability of rolling a 4 is p=1/4.

Let X be the random variable which indicates the the number of times that a 4 is rolled in n=12 trials. X has a Binomial distribution with parameters, number of trials n=12 and success probability p=1/4

a) The probability that number of 4 are rolled among 12 trials is

b) The average value of X is the expected value of X. Since X has a Binomial distribution, the expected value of X is

The average value of X is 3

The standard deviation of X is

c) X can take the values from 0 to 12. The different probabilities are

Since P(X=3)=0.2581 is the highest, X=3, 4s out of 12 rolls, has the highest likelihood of occuring.

2) Let Y be the IQ of a randomly selected person. Y has a normal distribution with mean and standard deviation

a) If a person has an IQ of 115, the proportion of the population that is expected to have an IQ higher than 115 is same as the probability that Y>115

The percentage of the population that is expected to have a higher IQ than a person with an IQ of 115 is 6.68%

b)  If a person has an IQ of 75, the proportion of the population that is expected to have an IQ lower than 75 is same as the probability that Y<75

The percentage of the population that is expected to have a lower IQ than a person with an IQ of 75 is 0.62%

c)  The proportion of the population, were the claim not false, that would be between the first score (83) and the second (212) is same as the probability that 83<Y<212

The percentage of the population, were the claim not false, that would be between the first score (83) and the second (212) is 95.54%


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